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nika2105 [10]
3 years ago
6

Find the value of x. Round the length to the nearest tenth.

Mathematics
2 answers:
SVEN [57.7K]3 years ago
4 0
I feel like your answer would be 9.2 cm
Reptile [31]3 years ago
4 0

Consider the given right triangle.

We have to find the value of 'x'.

Consider \tan 40^{\circ}

Since \tan \Theta =\frac{P}{B}

\tan 40^{\circ} = \frac{x}{11}

Finding the value of \tan 40^{\circ} from the calculator,

We get

\tan 40^{\circ} = 0.84

Now, 0.84 = \frac{x}{11}

x = 0.84 \times 11

x = 9.24

x = 9.2 (Rounded to nearest tenth)

So, the value of 'x' is 9.2 cm.

Option 3 is the correct answer.


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PLEASE HELP ME IM SO CONFUSED!!! i need answers 10-12
zimovet [89]

Answer: Heyaa! ~

   10. 8√2

   11. 2h²√3

   12. 2h³√5k⁴

Step-by-step explanation:

    <em>- Lets solve it together! </em>

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

Hopefully this helps you!

3 0
2 years ago
What is the slope of a line if X intercept is three and Y intercept is five
Ber [7]

Answer:

y=5x-15

Step-by-step explanation:

4 0
3 years ago
Evaluate the integral by making an appropriate change of variables.
VARVARA [1.3K]

By inspecting the integrand, the "obvious" choice for substitution would be

<em>u</em> = <em>y</em> + <em>x</em>

<em>v</em> = <em>y</em> - <em>x</em>

<em />

Solving for <em>x</em> and <em>y</em>, we would have

<em>x</em> = (<em>u</em> - <em>v</em>)/2

<em>y</em> = (<em>u</em> + <em>v</em>)/2

in which case the Jacobian and its determinant are

J=\begin{bmatrix}x_u&x_v\\y_u&y_v\end{bmatrix}=\dfrac12\begin{bmatrix}1&-1\\1&1\end{bmatrix}\implies|\det J|=\left|\dfrac12\right|=\dfrac12

The trapezoid <em>R</em> has two of its edges on the lines <em>x</em> + <em>y</em> = 8 and <em>x</em> + <em>y</em> = 9, so right away, we have 8 ≤ <em>u</em> ≤ 9.

Then for <em>v</em>, we observe that when <em>x</em> = 0 (the lowest edge of <em>R</em>), <em>v</em> = <em>y</em> ; similarly, when <em>y</em> = 0 (the leftmost edge of <em>R</em>), <em>v</em> = -<em>x</em>. So

-<em>x</em> ≤ <em>v</em> ≤ <em>y</em>

-(<em>u</em> - <em>v</em>)/2 ≤ <em>v</em> ≤ (<em>u</em> + <em>v</em>)/2

-<em>u</em> + <em>v</em> ≤ 2<em>v</em> ≤ <em>u</em> + <em>v</em>

-<em>u</em> ≤ <em>v</em> ≤ <em>u</em>

<em />

So, the integral becomes

\displaystyle\iint_R5\cos\left(7\frac{y-x}{y+x}\right)\,\mathrm dA=\int_8^9\int_{-u}^u\frac52\cos\left(\frac{7v}u\right)\,\mathrm dv\,\mathrm du

=\displaystyle\frac52\int_8^9\frac u7(\sin7-\sin(-7))\,\mathrm du

=\displaystyle\frac57\sin7\int_8^9u\,\mathrm du

=\displaystyle\frac5{14}\sin7(9^2-8^2)=\boxed{\frac{85}{14}\sin7}

4 0
2 years ago
Simply<br> (2k-9)^2+(k+2)^2=(2k+1)^2+(k-8)^2
vova2212 [387]

The square of a binomial expands as follows:

(a+b)^2=a^2+2ab+b^2

Expanding all the binomials, we have

4k^2-36k+81+k^2+4k+4=4k^2+4k+1+k^2-16k+64

Sum like terms:

5k^2-32k+85=5k^2-12k+65

Simplify terms appearing on both sides:

-32k+85=-12k+65

Move all terms involving k to the left and all numbers to the right:

-20k=-20

Divide both sides by -20:

k=1

6 0
3 years ago
If a construction work digs down to 30 feet below the surface of the ground. What is her elevation?
tresset_1 [31]

Answer:

-30 feet

Step-by-step explanation:

You are going down so it would be negative, if you were going up it would be posotive.

4 0
2 years ago
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