Width: x
Length: 2x
Perimeter=2x+2x+x+x=6x
32 cm more than width means x+32
6x=x+32
5x=32
x=6.4
Dimension is 6.4×12.8 (width×length)
Answer:
Step-by-step explanation:
<u>Given</u>
a)
- DC /AB = 3/2 ⇒
- DC = 3/2AB = 3/2p
b)
- BC = AD + (DC - AB)
- BC = q + (3/2p - p) = q + 1/2p
Answer:
length of one leg of the triangle is 64 cm.
Step-by-step explanation:
Given : The hypotenuse of a 45°-45°-90° triangle measures 128 cm.
To find : What is the length of one leg of the triangle.
Solution : We have given that hypotenuse of a 45°-45°-90° triangle measures 128 cm.
By the 45°-45°-90° triangle rule ,
Perpendicular sides (legs) are equal .
Hypotenuse = √2 × either perpendicular side ( leg ).
128 = √2 × leg .
We can write 128 as 64 √2 and substitute in above
64√2 = √2 leg.
On dividing by √2 both sides and switching sides.
leg = 64 cm .
Therefore, length of one leg of the triangle is 64 cm.
Answer:
The third option
y < -2x +2
y < or = 1/2x -1
y > or = -4
Step-by-step explanation:
Solved on Desmos graphing calculator ;)
Answer:
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Hope this helps you!
