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BlackZzzverrR [31]
2 years ago
6

Jenny is studying the growth of a particular type of plant. She is testing the effects of three growth factors: lighting, age, a

nd temperature. Here are the levels she's testing for each.
Growth factor Levels
Lighting Low, Medium, High, Very high
Age month, months, months, months, months
Temperature , , ,
She wants to find the number of ways of combining one level from each of the growth factors. How many ways are there?

Mathematics
1 answer:
Llana [10]2 years ago
7 0

Answer:

10 meses

Step-by-step explanation:

yo que se solo adivine :9

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Use the table to determine the location with the greatest amount of rainfall and the location with the least amount of rainfall.
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I think it is hilo hawii 480 cm it has the longest cm

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Follow me on brainy,and what is a+b+z+fg-y+up+f+r=​
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Sure why not.

Step-by-step explanation:

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Two lines passing through the point (2 , 3) intersect each other at an angle of 60° . If slope of one line is 2, then find the e
Lady bird [3.3K]

Hey there!

Same question is answered by me correctly.

You can go and check the answer link given:

brainly.com/question/25169246

<u>Note:</u>

The answer in the given link is answered by me.

4 0
3 years ago
Read 2 more answers
How do you read this expression 8(8x+7) and 8(3x)+8(7)
Misha Larkins [42]

Answer:

64x+56 & 24x+56

Step-by-step explanation:

I hope this is what you mean because this is not an equation as it is not set equal to anything.


Both problems solved by distributive property -

8*8x + (8*7) = 64x+56

8*3x + (8*7) = 24x+56

4 0
3 years ago
The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers
stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

(c) Confidence Interval for male expenditure is ($106.40, $136.40)

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

(c) Male

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0
4 years ago
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