Answer:
1/1000
Step-by-step explanation:
Answer:
I would choose A
Step-by-step explanation:
I chose A because it's an hypotenuse because of the different sides
David's score on his fifth test would be an 87. If you add up all the scores from his first to his fourth test, it would 363. However, since there are five tests, in order to get a 90 percent, the sum of all five test scores would be 450. 450 - 363 = 87.
Answer:
5/4k^2
Step-by-step explanation:
P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.
We will be using the following property of exponents:
\dfrac{a^x}{a^y}=a^{x-y}.
We have
P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.
Thus, the required product is \dfrac{5}{4k^2}.
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Answer:
Step-by-step explanation:
The answer is actually
Let:
S=1+2+3+4+5+6+7+8+9+n
We know the answer to the following infinite sum:
S2=1-1+1-1+1-1+1-1+1-1+1-1+1-....= - 1/2
We can therefore solve for this sum:
S3=1-2+3-4+5-6+7-8+9-....
We add them:
S3= 1-2+3-4+5-6+7-8...
S3= +1-2+3-4+5-6+7-8...
________________
2S3= 1-1+1-1+1-1+1-1+1-....
Therefore:
2S3=S2=
