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Mnenie [13.5K]
3 years ago
8

Cameron measured 65/100 inches of rain water on the first day of April. On the second day of April, he measured 83/100 inches of

rain water. How many inches of rain fell on the first 2 days of April?
Mathematics
1 answer:
Klio2033 [76]3 years ago
4 0
Add the inches together. 65+83=148 

Hence 148 inches
You might be interested in
Solve. −425=x−114 What is the solution to the equation? Enter your answer as a simplified mixed number in the box. FIRST PERSON
Maksim231197 [3]

Answer:

-311

Step-by-step explanation:

−425 = x − 114

=> x = -425 + 114

=> x = -311

Therefore, -311 is our answer.

Hoped this helped.

8 0
2 years ago
Pls help me solve it!
vekshin1

Answer:

A= 40°

B= 35°

C= 15°

Step-by-step explanation:

Since it says if the triangles were accurately drawn, then A would be the same  degree as Q. C would be the same degree as P. B would be the same degree as R. Since R's degree is missing I knew that a obtuse triangle was 90°. I added 40+15 and got 55. Then i subtracted 90-55 and got 35. So the unknown value would be 35°.

I hope this helps.

3 0
3 years ago
In the given figure, find ∠PQS, if∠PQR = 5x + 25 and∠SQR = 2x + 10.
kramer

Answer:

∠PQS= 3(x +5)

Step-by-step explanation:

∠PQR = 5x + 25

∠SQR+∠PQS= 5x+25

∠PQS = ∠PQR-∠SQR

∠PQS= (5x + 25 )-(2x + 10)

∠PQS = 5x+25 -2x-10

∠PQS= 3x +15

∠PQS= 3(x +5)

3 0
3 years ago
The Tabletop Games club, a student-led campus group, hosted a virtual concert last week to raise awareness about their club and
yarga [219]

Answer:

um i don't know this (i do im just lazy as heck)

Step-by-step explanation:

3 0
2 years ago
A metallurgist has an alloy with 5% titanium and an alloy with 30% titanium. He needs 100 grams of an alloy with 15% titanium. H
andrey2020 [161]
Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.3y\\
-----&-----&-------&-------\\
mixture&100&0.15&15
\end{array}
\\\\\\
\begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.3y=15\\
----------\\
0.5x+0.3\left( \boxed{100-x} \right)=15
\end{cases}

solve for "x"

what's "y"? well, y = 100 - x
4 0
3 years ago
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