Help !!!! Please number 1
1 answer:
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<h3>Answer: angle B = 47 degrees</h3>
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Work Shown:
Use law of cosines to find angle B
b^2 = a^2 + c^2 - 2*a*c*cos(B)
9^2 = 6^2 + 12^2 - 2*6*12*cos(B)
81 = 36 + 144 - 144*cos(B)
81 = 180 - 144*cos(B)
81 - 180 = -144*cos(B)
-99 = -144*cos(B)
-144*cos(B) = -99
cos(B) = (-99)/(-144)
cos(B) = 0.6875
B = arccos(0.6875)
B = 46.5674634422102
B = 47 when rounding to the nearest whole number
Make sure your calculator is in degree mode.
arccos is the same as inverse cosine often labeled on calculators.
f (x) = x ^ 4-x ^ 3 + x ^ 2-x
For this case what we can do is graph the function and see the behavior of it.
We have then that the function grows upwards (see attached image)
It has two cutting points with the x axis in:
x = 0
x = 1
Therefore, the other roots of the polynomial are imaginary.
Answer:
2 x intercepts appear on the graph of this polynomial function
For this case what we can do is graph the function and see the behavior of it.
We have then that the function grows upwards (see attached image)
It has two cutting points with the x axis in:
x = 0
x = 1
Therefore, the other roots of the polynomial are imaginary.
Answer:
2 x intercepts appear on the graph of this polynomial function