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Agata [3.3K]
3 years ago
8

Help !!!! Please number 1

Mathematics
1 answer:
Rudiy273 years ago
3 0

Answer:

Step-by-step explanation:

you have a special triangle 30-60-90

the ration in this traingle is x, x\sqrt{3} , 2x, where 2x is the hypothenuse

the hypothenuse is 12

x=12/2=6

the other leg is 6\sqrt{3}=10.39

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(-5)^2-2x(-9)+6<br> Please show work and step by step.
Varvara68 [4.7K]

Answer:

<h2>49</h2>

Step-by-step explanation:

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

==============================================

(-5)² - 2 × (-9) + 6          <em>first </em><em>E</em><em>xponents</em>

25 - 2 × (-9) + 6          <em>next </em><em>M</em><em>ultiplication</em>

25 + 18 + 6              <em>next </em><em>A</em><em>ddition</em>

43 + 6 = 49

5 0
3 years ago
Solve pls brainliestsss
Neko [114]

Lol

6x40=240mm squared

240mm^{2}

4 0
3 years ago
Read 2 more answers
Alemu, Tulu, Kassa and Tegitu worked for 4 hours, 6 hours, 5 hours
GaryK [48]
As a group they were paid $1000 after putting in 4+6+5+5 = 20 worker-hours.
$1000/(20 worker-hours) = $50/(worker-hour)
Alemu received 4*$50 = $200
Tulu received 6*$50 = $300
Kassa and Tegitu each received 5*$50 = $250
6 0
3 years ago
The sides of ∠A are tangent to circle k(O) with radius r. Find: r, if OA=14 dm, m∠A=90°.
Alex_Xolod [135]

Answer:

r = √98

Step-by-step explanation:

angle A and the diameter form an isosceles right triangle, with OA as the hypotenuse and r as the other sides. You can then make and solve an equation from the Pythagorean Theorem:

r^2 + r^2 = 14^2

2r^2 = 14^2

2r^2 = 196

r^2 = 98

r = √98

6 0
3 years ago
Read 2 more answers
A rectangular paperboard measuring 29in long and 20in wide has a semicircle cut out of it, as shown below.
katen-ka-za [31]

Here, we are required to find the area of the paper board given after the semicircle is cut out of it

Area of the paper board thatremains is 423 in²

Length = 29 in

Width = 20 in

Area of a rectangle = length × width

= 29 in × 20 in

= 580 in²

Area of a semi circle = πr²/2

π = 3.14

r = diameter / 2 = 20 in / 2 = 10 in

Area of a semi circle = πr²/2

= 3.14 × (10 in)² / 2

= 3.14 × 100 in² / 2

= 314 in²/2

= 157 in²

The semicircle is cut out of the rectangle

Find the area of the paper board that remains after the semicircle is cut out of it by subtracting the area of a semi circle from the area of a rectangle

Area of the paper board that remains = Area of a rectangle - Area of a semi circle

= 580 in² - 157 in²

= 423 in²

brainly.com/question/16994941

6 0
3 years ago
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