Answer:
a=3
Step-by-step explanation:
24= -3(2a-15)-a -->given
24=-6a+45-a -->distribute the -3
24=-7a+45 -->combine like terms
-21=-7a -->subtract 45 from both sides
3=a -->divide both sides by -7
The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
Answer:
I believe the answer is 9 years old or 8 years old.
Answer:
Jada error was he multiplied the equation by (-9/4) to make the coefficient of x one. He should have multiplied it by 108
Step-by-step explanation:
Jada solved the equation
-4/9 = x/108
using the steps below:
-4/9 = x/108
(-4/9)(-9/4) = (x/108)(-9/4)
x = -1/48
Jada should have multiplied through by 108, instead of (-4/9). That was the error he made.
Multiplying through by 108 gives
(-4/9)(108) = (x/108)(108)
-48 = x
x = -48
The answer should have been
x = -48
and not
x = -1/48
