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4 years ago

Oz= 1 c please help with this question

Mathematics

1 answer:

MaRussiya [10]4 years ago

8 0

The answer is 8

hope this helped :)
alisa202

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3 years ago

If we approximate the function y=sin(x) with a0+a1 x a2 x^2 +a3 x^3, what is a0,a2,a2,a3?

Rashid [163]

The coefficients $a_0,a_1,a_2,a_3$ could be chosen to be the coefficients in the Maclaurin series of $\sin(x)$ .

We have

$y = \sin(x) \approx a_0 + a_1 x + a_2 x^2 + a_3 x^3 \\\\ \implies y(0) = 0 = a_0$

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2 years ago

Which of the following expressions does not equal: the sixth root of 81x^4y^8

DerKrebs [107]

$\sqrt[6]{81x^4y^8}=\left[3^4x^4(y^2)^4\right]^\frac{1}{6}=\left[\left(3xy^2\right)^4\right]^\frac{1}{6}\\\\=\left(3xy^2\right)^{4\cdot\frac{1}{6}}=\left(3xy^2\right)^\frac{2}{3}\to A\\\\=\left(3xy^2\right)^\frac{2}{3}=\sqrt[3]{\left(3xy^2\right)^2}=\sqrt[3]{9x^2y^4}\to D\\\\=\left(3xy^2\right)^\frac{2}{3}=\left(3x\right)^\frac{2}{3}y^{2\cdot\frac{2}{3}}=\left(3x\right)^\frac{2}{3}y^\frac{4}{3}\to B\\\\\\Answer:C$

4 0

4 years ago

<img src="https://tex.z-dn.net/?f=y%5E2%2B3y%2B2%3D0" id="TexFormula1" title="y^2+3y+2=0" alt="y^2+3y+2=0" align="absmiddle" cla

Semmy [17]

Answer:

y = - 2, y = - 1

Step-by-step explanation:

y² + 3y + 2 = 0

Consider the factors of the constant term (+ 2) which sum to give the coefficient of the y- term (+ 3)

The factors are + 2 and + 1 , since

2 × 1 = 2 and 2 + 1 = 3 , then

(y + 2)(y + 1) = 0

Equate each factor to zero and solve for y

y + 2 = 0 ⇒ y = - 2

y + 1 = 0 ⇒ y = - 1

5 0

3 years ago