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4 years ago

14

Oz= 1 c please help with this question

1 answer:

MaRussiya [10]4 years ago

8 0

The answer is 8

hope this helped :)
alisa202

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Divide -2 1/2 divided by 6

Montano1993 [528]

the correct answer would be -5/12

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3 years ago

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PLEASE HELP, IM DYING FOR THE ANSWER RIGHT NOW, PLZ HELP!

vlabodo [156]

3.2x - 6 + (-5.6x + 4) = -2.4x - 2
Hope this helps!

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3 years ago

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Help me find the figure , area formula and graph the dots and find the area

Advocard [28]

Answer:

Looking at the given points we know that it is going to be a triangle because it only have 3 points. Therefore the figure is a triangle and the area formula would be $A=\frac{1}{2}*b*h$ .

You can look at the attached graph and what we see is that our height of the triangle is from $y=-3$ to $y=4$ which means that our height is 7 units high. We can also see that our base starts at $x=-4$ and ends at $x=4$ making us have a base of 8 units.

<u>We then plug in the values and solve</u>

$A = \frac{1}{2}*7\ units * 8\ units$

$A = \frac{1}{2}*56\ units^2$

$A = 28\ units^2$

Therefore, the area of our triangle is $28\ units^2$

Hope this helps! Let me know if you have any questions

4 0

2 years ago

From start to finish, a machine can fill a bottle of water, seal it, label it, and pack it in 8.6 seconds. About how many bottle

levacccp [35]

Or take about 55 bottles

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3 years ago

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Determine the amount needed such that when it comes time for retirement, an individual can make monthly withdraws in the amount

bazaltina [42]

Answer:

The amount needed such that when it comes time for retirement is $396721.78.

Step-by-step explanation:

Given : An individual can make monthly withdraws in the amount of $2,154 for 30 years from an account paying 5.1% compounded monthly.

To find : The amount needed such that when it comes time for retirement?

Solution :

Using the formula of monthly payment,

Monthly payment, $M=\frac{\text{Amount}}{\text{Discount factor}}$

Discount factor D=\frac{1-(1+i)^{-n}}{i}

Where,

Amount = ?

Monthly payment M=$2154

Rate r= 5.1%=0.051

$i=\frac{0.05}{12}=0.00425$

Time = 30 years

$n=30\times12=360$

Substitute all the values,

$D=\frac{1-(1+i)^{-n}}{i}$

$D=\frac{1-(1+0.00425)^{-360}}{0.00425}$

$D=\frac{1-(1.00425)^{-360}}{0.00425}$

$D=\frac{1-0.21723}{0.00425}$

$D=\frac{0.78277}{0.00425}$

$D=\$184.1811$

Monthly payment, $M=\frac{\text{Amount}}{\text{Discount factor}}$

$2154=\frac{A}{184.1811}$

$A=2154\times 184.1811$

$A=\$396721.778$

Nearest cent, $A=\$396721.78$

Therefore, the amount needed such that when it comes time for retirement is $396721.78.

6 0

4 years ago