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timama [110]
3 years ago
5

At a snack stand, drinks cost $1.50. Write the expression that could be used to find the total cost in dollars of d drinks?

Mathematics
2 answers:
vichka [17]3 years ago
7 0
1.50 times x because the other number is unknown
max2010maxim [7]3 years ago
5 0

Equation:

$1.50 * x = d

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862.4×0.03? A.25.872 B.258.720 C.2587.200 D.25,872.000
den301095 [7]
<h2>Greetings!</h2>

Answer:

A) 25.872

Step-by-step explanation:

A tip when multiplying numbers that are decimals, make the numbers whole numbers without decimals:

862.4 * 10 = 8624

0.03 * 100 = 3

8624 * 3 = 25,872

Then divide by the amount you multiplied the numbers by:

25,872 ÷(100 * 10) = 25.872

So your answer is A) 25.872


<h2>Hope this helps!</h2>
5 0
3 years ago
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X³+y³+z³=k <br> If u get a right answer its going to be marked brainliest
scoray [572]

Answer:

x3+y3+z3

Step-by-step explanation:

hope it helps

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Let v be the vector from initial point upper p 1p1 to terminal point upper p 2p2. write v in terms of i and j.
Umnica [9.8K]
I reallly dont know but that long is going to end up long
6 0
3 years ago
Which fraction represents the decimal 0.12
ryzh [129]

Answer:

\dfrac 3{25}

Step-by-step explanation:

0.12 = \dfrac{12}{100}=\dfrac{3}{25}

8 0
2 years ago
a number is equal to twice a smaller number plus 3. The same number is equal to twice the sum of the smaller number and1. How ma
NeX [460]

Answer:

There is NO solution

Step-by-step explanation:

Considering 'y' be the number

Considering x be the smaller number

As 'y' is equal to twice a smaller number plus 3.

so

y = 2x + 3

also

y is equal to twice the sum of the smaller number and 1.

so

y = 2x + 1

so the system of equations become

y = 2x + 3

y = 2x + 1

solving

\begin{bmatrix}y=2x+3\\ y=2x+1\end{bmatrix}

\mathrm{Subsititute\:}y=2x+1

\begin{bmatrix}2x+1=2x+3\end{bmatrix}

\mathrm{Refine\:}2x+1=2x+3

-2=0

-2=0\:\mathrm{\:is\:false,\:therefore\:the\:system\:of\:equations\:has\:no\:solution}

\mathrm{No\:Solution}

Therefore, there is NO solution.

7 0
2 years ago
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