<span>The definition of quadratic function is given by:
</span>

<span>
So the problem asks for two conditions:
<em>1. Write the quadratic function in factored form.
</em>
<em>2. The vertex has an x-coordinate of 3.</em>
Then the equation (1) must be written as follows:
</span>

<span>
To satisfy the two conditions:
So we are free to choose the value of one root, say:

Thus:
Finally,
the answer is:

The graph of this function is shown in the figure below.</span>
Answer:
$4
Step-by-step explanation:
The two purchases can be written in terms of the cost of an adult ticket (a) and the cost of a student ticket (s):
7a +16s = 120 . . . . . . . . price for the first purchase
13a +9s = 140 . . . . . . . . price for the second purchase
Using Cramer's rule, the value of s can be found as ...
s = (120·13 -140·7)/(16·13 -9·7) = 580/145 = 4
The cost of a student ticket is $4.
_____
<em>Comment on Cramer's Rule</em>
Cramer's rule is particularly useful for systems that don't have "nice" numbers that would make substitution or elimination easy methods to use. If you locate the numbers in the equation, you can see the X-patterns that are used to compute the numerator and denominator differences.
The value of a is (16·140 -9·120)/(same denominator) = 1160/145 = 8. I wanted to show you these numbers so you could see the numerator X-pattern for the first variable.
__
Of course, graphical methods can be quick and easy, too.
Hello!
As we can see, they sell 2/5 as many white milks and chocolate milks. We can write this as the ratio 2:5. As you can see, we are given the total, which is 35. The total of the ratio in simplest form is 7 (2+5). As you can see, we have to multiply by 5 to get that 7 to 35. Therefore we multiply each part of the ratio by 5 to get our final answer. We can have w represent the white milks while c represents the chocolate milks.

·

=
Therefore there were 25 chocolate milks sold (just to verify 10 is 2/5 of 25).
I hope this helps!
In solving a, we must get the formula needed then substitute
the given so we have
A=πr2
dA/dt=1,400 km2/s
then solve for dA/dt
<span>1400</span><span> <span>k<span>m2</span>/</span></span><span>s=2<span>π(</span><span>8000</span></span><span> <span>km</span>)<span><span>dr</span><span>/dt</span></span></span>
<span>
<span>dr</span><span>dt</span>≈<span>0.028</span><span> <span>km</span>/</span>s
</span>
In solving b,
its just the same as solving the letter a, the only difference is that the
radius is not given so we get the formula for A, then substitute
<span>640</span>,<span>000</span> k=<span>π<span>r2</span>⟹</span>r≈<span>451.352</span> <span>km</span>
Then solve for
dAdt
1,<span>400</span><span> <span>k<span>m2</span>/</span></span><span>s=2<span>π(</span><span>451.352</span></span><span> <span>km</span>)<span><span><span>dr</span><span>dt</span></span>⟹</span><span><span><span>dr</span><span>dt</span></span>≈</span><span>0.494</span></span><span> <span>km</span>/</span><span>s</span>