F(x) = -4x^7 +x^3 -x^2 +5
a) It is a degree 7 polynomial, so will have 7 zeros (some may be repeated).
b) has 3 sign changes, so 1 or 3 positive real zeros. If odd powers have their signs reversed, the signs are changed to +--+, so there are 2 sign changes. There will be 0 or 2 negative real zeros.
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There is actually 1 positive real zero and 0 negative real zeros. This means there are 3 conjugate pairs of complex zeros.
Answer:
I think graph represent x>2. or (2,infinity)
Hey there!
2(x - 3) / y = 5
2(x - 3) / 5 = 5
2(x) + 2(-3) / 5 = 5
(2x - 6) 5 = 5
MULTPLY 5 to BOTH SIDES
(2x - 6)/5 * 5 = 5 * 5
SIMPLIFY IT!
2x - 6 = 5 * 5
2x - 6 = 25
ADD 6 to BOTH SIDES
2x - 6 + 6 = 25 + 6
SIMPLIFY IT!
2x = 25 + 6
2x = 31
DIVIDE 2 to BOTH SIDES
2x/2 = 31/2
SIMPLIFY IT!
x = 31/2
x = 15 1/2
Therefore, the answer should be:
x = 15 1/2
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
The answer is C: 4.4
It might be A at the same time tho LMOO
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s