Answer:
<em>The three options that should be chosen are: B, D, E</em>
Step-by-step explanation:
We are given the ratio 5:2 and are required to find 3 equivalent ratios from the provided list.
To find which of the ratios of the list are equivalent to 5:2, we have to simplify them by dividing by a common number.
A 2:5 This ratio is already simplified and it's not equivalent to 5:2
B 10:4. Dividing both numbers by 2 we get 5:2. This option is correct
C 20:50 Dividing by 10 we get 2:5 and it's not equivalent to 5:2
D 35:14 Dividing both numbers by 7 we get 5:2. This option is correct
E 55:22 Dividing both numbers by 11 we get 5:2. This option is correct
Thus, the three options that should be chosen are: B, D, E
Answer:
C. 33.2%
Step-by-step explanation:
Number of trials n = 85
Probability of success p = 0.5
Number of successes r = 40
Use cumulative binomial probability:
P(x ≤ r) = binomcdf(n, p, r)
P(X ≤ 40) = binomcdf(85, 0,5, 40)
P(x ≤ 40) = 0.332
Answer:
Step-by-step explanation:
Stop trying to get people to do your work for you
+5*7=c
Mass = volume × density;
mass = 2.5g/mL x 15mL;
mass = 37.5g;
Answer:
4.6%.
Step-by-step explanation:
The probability that a can of paint contains contamination(C) is 3.23%
P(C)=3.23%
The probability of a mixing(M) error is 2.4%.
P(M)=2.4%
The probability of both is 1.03%.
![P(C \cap M)=1.03\%](https://tex.z-dn.net/?f=P%28C%20%5Ccap%20M%29%3D1.03%5C%25)
We want to determine the probability that a randomly selected can has contamination or a mixing error. i.e. ![P(C \cup M)](https://tex.z-dn.net/?f=P%28C%20%5Ccup%20M%29)
In probability theory:
![P(C \cup M) = P(C)+P(M)-P(C \cap M)\\P(C \cup M)=3.23+2.4-1.03\\P(C \cup M)=4.6\%](https://tex.z-dn.net/?f=P%28C%20%5Ccup%20M%29%20%3D%20P%28C%29%2BP%28M%29-P%28C%20%5Ccap%20M%29%5C%5CP%28C%20%5Ccup%20M%29%3D3.23%2B2.4-1.03%5C%5CP%28C%20%5Ccup%20M%29%3D4.6%5C%25)
The probability that a randomly selected can has contamination or a mixing error is 4.6%.