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anastassius [24]
3 years ago
12

What is the Range of this Graph? ASAP

Mathematics
1 answer:
Flura [38]3 years ago
6 0

Answer:

The range would be {-4,-3,1,6}

Step-by-step explanation:

Individual points are bracketed

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-282y

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A tessellation is the regular _____ of a plane shape.
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Step 3: Displaying numerical data in dot plots, and describing and analyzing
mylen [45]

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81

Step-by-step explanation:

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4 0
3 years ago
Answer the question to become brainliest
marishachu [46]

Answer:

2406.17 cm³

Step-by-step explanation:

The following data were obtained from the question:

Height (h) = 24.4 cm

Base length (L) = 17.2 cm

Volume (V) =?

Next, we shall determine the base area of the pyramid. This can be obtained as follow:

Base length (L) = 17.2 cm

Base area (B) =.?

B = L × L

B = 17.2 × 17.2

B = 295.84 cm²

Finally, we shall determine the volume of the pyramid. This can be obtained as follow:

Height (h) = 24.4 cm

Base area (B) = 295.84 cm²

Volume (V) =?

V = ⅓Bh

V = ⅓ × 295.84 × 24.4

V = 2406.17 cm³

Thus, we volume of the pyramid is 2406.17 cm³

7 0
3 years ago
A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a
sdas [7]

Answer:

y=-\dfrac{13}{49}x^2

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

y=ax^2+bx+c

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

-13=a(-7)^2+b(-7)+c

49a-7b+c=-13

(x,y) = (7,-13)

-13=a(7)^2+b(7)+c

49a+7b+c=-13

(x,y) = (0,0)

0=a(0)^2+b(7)+c

c=0

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13

49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13

we can solve these two equation using the elimination method, by simply adding the two equations

\quad\quad49a-7b=-13\\+\quad49a+7b=-13

------------------------------

\quad\quad 98a=-26

\quad\quad a=-\dfrac{13}{49}

Now we can plug this value of a in any of the two equations.

49a-7b=-13

49\left(-\dfrac{13}{49}\right)-7b=-13

-13-7b=-13

-7b=0

b=0

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

y=\left(-\dfrac{13}{49}\right)x^2+0x+0

y=-\dfrac{13}{49}x^2

49y=-13x^2

This our equation of the arch!

5 0
3 years ago
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