1 - Derivative of arcsin x.
<span>
The derivative of f(x) = arcsin x is given by
</span><span> f '(x) = 1 / sqrt(1 - x 2) </span><span>
</span>2 - Derivative of arccos x.
<span>
The derivative of f(x) = arccos x is given by
</span><span> f '(x) = - 1 / sqrt(1 - x 2) </span><span>
</span>3 - Derivative of arctan x.
<span>
The derivative of f(x) = arctan x is given by
</span><span> f '(x) = 1 / (1 + x 2) </span><span>
</span>4 - Derivative of arccot x.
<span>
The derivative of f(x) = arccot x is given by
</span><span> f '(x) = - 1 / (1 + x 2) </span><span>
</span>5 - Derivative of arcsec x.
<span>
The derivative of f(x) = arcsec x tan x is given by
</span><span> f '(x) = 1 / (x sqrt(x 2 - 1))</span><span>
</span>6 - Derivative of arccsc x.
<span>
The derivative of f(x) = arccsc x is given by
</span><span> f '(x) = - 1 / (x sqrt(x 2 - 1)) </span><span>
</span>
Answer:
Distribute
Step-by-step explanation:
Distribute . 9x+18=90
Subtract 9x=72
Divide x=8
Answer:
x ≈ 36.9°
Step-by-step explanation:
Using the sine ratio in the right triangle, that is
sinx = 
= 
, then
x = 
( ) ≈ 36.9° ( to 1 dec. place )
Answer:
They do not run at the same rate because Jada ran at a rate of .150km per min, while Andre ran at .133333 km per minute.
Step-by-step explanation:
Andre ran : 2km/15min = .133333km per min
Jada ran: 3km/20min=.150km per minute
.150>.1333, so Jada ran at a higher rate of kilometers per minute.
Answer:
2/3*3/3
Step-by-step explanation:
I mean its just doing 2/3 * 1 which i mean, 3/3 is still a fraction so i did it (TBH cant think of anything else
