The given quadrilateral is a kite.
Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)
Firstly, we find the distance between AD and DC
AD = 
⇒ AD = 
⇒ AD = 5
DC = 
⇒ DC = 
⇒ DC = 5
Hence, AD = DC = 5
Now, find the distance between AB and BC
AB = 
⇒ AB = 
⇒ AB = 
⇒ AB = 
BC = 
⇒ BC = 
⇒ BC = 
⇒ BC = 
Hence, AB = BC = √97
In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.
Hence, it follows the property of kite.
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0.8x=40
x=40÷0.8=50
so the original price is 50
(3^8 ⋅ 2^-5 ⋅ 9^0)^-2 ⋅ (2^ -2 / 3^3) ^4 ⋅ 3^28 =
(6561 * 0.03125 * 1)^2 * (0.00925)^4 * 22876792454961 =
42037.81348 * 0.00000000732094 * 22876792454961 =
7040477235.56798349
round answer as needed
Answer:
AC = 12.38 cm
Step-by-step explanation:
When there are 2 pairs given, we can use the sine rule to solve the problem.
By pairs we mean "an angle and side opposite to it"
<em>1 pair is 85.2 degree angle and 13 cm, and another pair is 71.6 degree angle and the side AC (which we want to figure out).</em>
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Sine Rule is given by 
where,
A and B are the two respective angles and a and b are the two respective sides (of the pairs). Plugging all the info and using algebra, we have:

Thus, AC = 12.38 cm