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3 years ago

6

I have a homework project in math and I don’t know how to do it can anybody help? I am really bad at math. It says 118/13=59/z t

hen wants me to give it an answer ik the answer 6.5 but I just don’t know how to do it someone explain please.

1 answer:

adoni [48]3 years ago

8 0

Take 13×59=767 then you divide 767÷118=your answer 6.5.

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Your beginning checkbook balance on Sunday morning is $417.83. On Monday you buy groceries for $189. 12 and purchase a meal on T

Ahat [919]

Answer:

320.82

Step-by-step explanation:

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3 years ago

In your lab, a substance's temperature has been observed to follow the function T(x) = (x + 5)3 + 7. The turning point of the gr

kompoz [17]

A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.

t(x)=(x+5)^3+7

dt/dx=3(x+5)^2

d2t/dx2=6(x-5)

dt/dx=0 only when x=-5

However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.

So there is no turning point for this function.

Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.

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3 years ago

Given that f(x) = x + 3<br> a) Find f(2)

Nataly_w [17]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

In the above question, it is given that :

$\qquad \sf \boxed{ \sf f(x) = \frac{x + 3}{2} }$

A.) Find f(2) :

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{2 + 3}{2}$

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{5}{2}$

or

$\qquad \sf \dashrightarrow \: f(2) = 0.5$

B.) Find ${ \sf {f}^{-1}(x) }$ :

$\qquad \sf \dashrightarrow \: let \: y = f (x)$

so, we can write it as :

$\qquad \sf \dashrightarrow \: y = \dfrac{x + 3}{2}$

$\qquad \sf \dashrightarrow \: 2y = x + 3$

$\qquad \sf \dashrightarrow \: x = 2y - 3$

Now, put x = ${ \sf {f}^{-1}(x) }$ , and y = x and we will get our required inverse function ~

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3$

C.) Find ${ \sf {f}^{-1}(12) }$ :

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 36- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 33$

7 0

1 year ago

Find the equation of the line parallel to the graph of 4x-5y=-1 that contains the point (1,3)

rewona [7]

Answer:

To find the equation of the line parallel to the graph, first of all find the slope of the graph by making y the subject of the formula and comparing the resulting equation with y = mx + c , knowing fully well that m stands for the slope.

So, from the equation of the graph give, y = 4x/5 +1/5, therefore the slope is 4/5. For a line to be parallel to the graph then they must have the same slope, to find the equation of the line at the given point, then we use the formula

y - y1 = m ( x - x1 )

y - 3 = 4/5 ( x - 1 )

multiply through by 5

5( y - 3 ) = 4 ( x - 1)

5y - 15 = 4x - 4

5y - 4x = - 4 + 15

so, 5y - 4x = 11 is the equation

Step-by-step explanation:

4 0

3 years ago

Solve for d<br> Can you pls help me?

Georgia [21]

The answer to this question would be 3d-2=31 and d=11

3 0

3 years ago