Answer:
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 71 inches and standard deviation 4 inches.
(a) What is the probability that an 18-year-old man selected at random is between 70 and 72 inches tall? (Round your answer to four decimal places.)
z1 = (70-71)/4 = -0.25
z2 = (72-71/4 = 0.25
P(70<X<72) = p(-0.25<z<0.25) = 0.1974
Answer: 0.1974
(b) If a random sample of thirteen 18-year-old men is selected, what is the probability that the mean height x is between 70 and 72 inches? (Round your answer to four decimal places.)
z1 = (70-71)/(4/sqrt(13)) = -0.9014
z2 = (72-71/(4/sqrt(13)) = 0.9014
P(70<X<72) = p(-0.9014<z<0.9014) = 0.6326
Answer: 0.6326
please mark me the brainiest
Answer:$20
Step-by-step explanation:
If Carlos had $20
Ben would have $60
And Ava would have $40
Answer:
197.192
Step-by-step explanation:
62.8x3.14=197.192
Answer:
(x + 2) + (–5x + 4) / (x² – 2x + 1)
Step-by-step explanation:
(x³ – 8 x + 6) ÷ (x² – 2x + 1)
The operation can be carried out as follow:
Please see attached photo for details.
(x³ – 8 x + 6) ÷ (x² – 2x + 1) =
(x + 2) + (–5x + 4) / (x² – 2x + 1)
Answer:
C. 707 cm^2
Step-by-step explanation:
