Answer:
The unit vector u is (-5/√29) i - (2/√29) j
Step-by-step explanation:
* Lets revise the meaning of unit vector
- The unit vector is the vector ÷ the magnitude of the vector
- If the vector w = xi + yj
- Its magnitude IwI = √(x² + y²) ⇒ the length of the vector w
- The unit vector u in the direction of w is u = w/IwI
- The unit vector u = (xi + yj)/√(x² + y²)
- The unit vector u = [x/√(x² + y²)] i + [y/√(x² + y²)] j
* Now lets solve the problem
∵ v = -5i - 2j
∴ IvI = √[(-5)² +(-2)²] = √[25 + 4] = √29
- The unit vector u = v/IvI
∴ u = (-5i - 2j)/√29 ⇒ spilt the terms
∴ u = (-5/√29) i - (2/√29) j
* The unit vector u is (-5/√29) i - (2/√29) j
Answer:
-5.1, -5, -4.5, -4.45,-4 2/5
Answer:
-64
Step-by-step explanation:
a(b - c)
a = -8
b = 12
c = 4
So, you'd plug in those numbers:
-8(12 - 4)
You'd start within the parenthesis's, so:
(12 - 4), which equals (8)
-8(8)
= -64
Points on given line = (-12,-2) and (0,-4) because you can see them on the graph. Then draw a parallel line thru (0,6)
To get from (0,-4) to (0,6) your x stays constant and your y coordinate increased by 10. So your new point will do the same in relation to (-12,-2) the x will stay constant at -12 and your y will increase by 10 to +8.
So the answer is A (-12,8)
You can check this because parallel lines have the same slope so
y2-y1/x2-x1 should be equal for both lines.
Line 1: -4 - (-2) / 0 - (-12) = -2/12 = -1/6
Line 2: 6 - 8 / 0 - (-12) = -2/12 = -1/6
Answer:
D
Step-by-step explanation:
