Answer:
The required point is P(-7,
) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7
Step-by-step explanation:
Given equation of line is 2x-6y=7
To find point on graph whose x-coordinate twice the y-coordinate:
Let y be y-coordinate of point
Hence, x-coordinate of point will be 2y
The required point is P(2y,y) on equation of line 2x-6y=7
Now,
2x-6y=7
2(2y)-6y=7
-2y=7
y=
Thus,
The required point is P(-7,)
Note: Figure show equation of line red line and point P as blue dot.
I honestly don’t understand
The answer is C.) 4 1/4 and 5 1/2
Answer:
316.0
Step-by-step explanation:
In the US, the given number is in standard form.
__
In the UK, "standard form" is what we refer to as "scientific notation" in the US. The number in standard form there is ...
3.160×10²
Answer:
21.25
Step-by-step explanation:
We can use the Pythagorean theorem to solve
We have the two legs and are looking for the hypotenuse
a^2 + b^2 = c^2
17^2 +12.75 ^2 = c^2 where c is the diagonal
289 +162.5625 = c^2
451.5625 = c^2
Take the square root
sqrt(451.5625) = sqrt(c^2)
21.25 =c
