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maxonik [38]
3 years ago
7

BRAINLIEST IF CORRECT!!!

Mathematics
2 answers:
Naddik [55]3 years ago
7 0

Answer:

X=1

Step-by-step explanation:

1+3=4

6*4=24

LenKa [72]3 years ago
3 0

Answer:

X=1

Step-by-step explanation:

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Given the following quadratic equation, find the average rate of change
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Answer: The average rate of change is 1 over 3, or just 1/3. The y-values change 1 unit every time the x-values change 3 units, on this interval! hope this helps
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Price of 50 kg rice rupees 7650 find the price of 1 kg rice​
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price of 50 kg rice rupees 7650 find the price of 1 kg rice

so 50kg: 7650r

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6 0
3 years ago
If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how
Goryan [66]

Rates are used to measure a quantity over another.

<em>The 1.8 million cars use </em>1.85 \times 10^{10}<em> liters each year</em>

Given

Cars = 1.8\ million

d = 17500km --- distance

r = 40miles/gallon

First, we calculate the number (n) of gallons used by each car

r = \frac{d}{n}

Solve for n

n = \frac{d}{r}

So, we have:

n = \frac{17500km}{40miles/gallon}

n = \frac{17500km}{40miles}gallon

Convert miles to kilometers

n = \frac{17500km}{40km \times 1.60934}gallon

n = \frac{17500km}{64.3738km}gallon

n = 271.85\ gallon

The number of gallons (N), used by all the cars is:

N = n \times cars

N = 271.85 \times 1.8\ million

N = 489330000

Convert to liters

N = 489330000 \times 3.78541L

N = 1852314675.3L

In scientific notation to 2 decimal places, we have:

N = 1.85 \times 10^{10}L

<em>Hence, the number of liters used is </em>1.85 \times 10^{10}<em />

Read more about distance and rates at:

brainly.com/question/24659604

4 0
3 years ago
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