Sum of nth term of arithmetic sequence is given by Sn = n/2[2a + (n - 1)d]
Here, a = 6, n = 26 and d = 14 - 6 = 8
S26 = 26/2[2(6) + (26 - 1)8] = 13[12 + 25(8)] = 2,756
Answer:
Step-by-step explanation:
a/(b+c) < 2a/(a+b+c)
b/(a+c) < 2b/(a+b+c)
c/(a+b) <2c/ (a+b+c)
so a/(b+c)+b/(a+c)+c/(a+b) <2(a+b+c)/(a+b+c)=2
Answer:
2:1/2
5:16/24
10:Movie B
11:Movie D
12:2/3
I can't see 29. If you show it, then i will solve it.
Step-by-step explanation:
Answer:
A.-10 should be the answer to the question..
