Question

What is the distance???

Answer 1

Answer:

5

Step-by-step explanation:

Answer 2

Answer:

5

Step-by-step explanation:

$distance = \sqrt{(x2-x1)^2+(y2-y1)^2}$

$\sqrt{(4-4)^2+(2-(-3))^2}$

Simplify.

$\sqrt{0^2+5^2} = \sqrt{25}$

$\sqrt{25} = \sqrt{5^2}$

Pull terms out from under the radical, assuming positive real numbers.

5

good luck, hope this helps :)