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3 years ago

I need help with 12 and 13 pls!

Mathematics

2 answers:

balu736 [363]3 years ago

8 0

Answer:

12 the midpoint is (2,5)

13 z (3,7)

Step-by-step explanation:

andriy [413]3 years ago

3 0

Answer:

12 the midpoint is (2,5)

13 z (3,7

Step-by-step explanation:

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HELP plssssssssssssssssssssssss

hoa [83]

Answer: 8.5

Step-by-step explanation: 8.5 because 34 divided by 4 is 8.5. To find the unit rate, make 4 hours turn to 1 hour. To do that, divided 4 by 4. Do the same with the other number, which is 34. 34 divided 4 is equal to 8.5

7 0

3 years ago

Read 2 more answers

What is the solution to the equation?

Oxana [17]

ANSWER

EXPLANATION

The given equation is

$\frac{ - 3d}{ {d}^{2} - 2d - 8} + \frac{3}{d - 4} = \frac{ - 2}{d + 2}$

Factor the first fraction to get,

$\frac{ - 3d}{(d + 2)(d - 4)} + \frac{3}{d - 4} = \frac{ - 2}{d + 2}$

Multiply through by (d+2)(d-4)

$- 3d + 3(d + 2) = - 2(d - 4)$

Expand:

$- 3d + 3d + 6 = - 2d + 8$

$6 = - 2d + 8$

$6 - 8= - 2d$

$- 2 = - 2d$

divide both sides by -2

$d = 1$

7 0

3 years ago

Read 2 more answers

an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a

viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is; $\mathbf{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t

Then the similar triangles ΔOCD and ΔOAB is as follows:

$\dfrac{h}{r}= \dfrac{20}{8}$ ( similar triangle property)

$\dfrac{h}{r}= \dfrac{5}{2}$

$\dfrac{h}{r}= 2.5$

h = 2.5r

$r = \dfrac{h}{2.5}$

The volume of the water in the tank is represented by the equation:

$V = \dfrac{1}{3} \pi r^2 h$

$V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h$

$V = \dfrac{1}{18.75} \pi \ h^3$

The rate of change of the water depth is :

$\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

$\dfrac{dv}{dt}= - 4 \ ft^3/sec$

Therefore,

$-4 = \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

the rate of change of the water at depth h = 10 ft is:

$-4 = \dfrac{ 100 \ \pi }{6.25}\ \dfrac{dh}{dt}$

$100 \pi \dfrac{dh}{dt} = -4 \times 6.25$

$100 \pi \dfrac{dh}{dt} = -25$

$\dfrac{dh}{dt} = \dfrac{-25}{100 \pi}$

Thus, the rate of change of the water depth when the water depth is 10 ft is; $\mathtt{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

4 0

3 years ago

WHOEVER GIVES THE BEST ANSWER WILL BE MARKED AS BRAILIEST!!!!!!!!!!

mojhsa [17]

Answer:

Step-by-step explanation:

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3 years ago

doctors use gallium in scanning some patients for diseases the table shows the amount of gallium in mg remaining in a patients s

Blababa [14]

Step-by-step explanation:

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2 years ago