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nika2105 [10]
3 years ago
5

CAN U GUYS PELASE ANSWER THE SIMULTANEOUS EQUATION QUESTION QUESTIONS ASAP. THIS IS EXTREMELY URGENT. Solve it by using the subs

titution method. Do questions a and d

Mathematics
1 answer:
prisoha [69]3 years ago
6 0

Answer:

a ) y = 1 and x = -1

d) y = 5 and x = -1/2

Step-by-step explanation:

<h2><u>Substitution method</u></h2><h2><u>Question a</u></h2>

y = x+ 2

y = 2x + 3

<em>we can make the first formula in terms of x , so we can place in into the second formula</em>

y = x + 2

x = y -  2

now put y - 2 where x is in the second equation

y = 2x + 3

y = 2(y - 2) + 3

y = 2y - 4 +3

now solve

4 - 3 = 2y -y

y = 1

since y = 1 we can find what x is by putting into the first formula

y = x +2

x = y - 2

x = (1) -2

x = -1

<h3><u>hence y = 1 and x = -1 </u></h3><h3><u /></h3><h2><u>Question d</u></h2>

y = 2x + 6

y = 4 - 2x

<em>we can make the first formula in terms of x , so we can place in into the second formula</em>

y = 2x + 6

y - 6 = 2x

x = (y-6)/ 2

now place (y-6)/2 where x is in the second formula

y = 4 -2x

y = 4 - 2 (\frac{y - 6}{2})

now solve

the multiplication by 2 and division by 2 are cancelled out

hence making the simplified equation as:

y = 4 - y + 6

2y = 4 + 6

2y = 10

y = 5

now place this into the first equation

y = 2x + 6

y - 6 = 2x

x = (y-6)/ 2

x = (5-6)/2

x = -1/2

<h3><u>hence y = 5 and x = -1/2</u></h3>

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