Answer:
2
Step-by-step explanation:
substitute n=1 and n=3 in the given equation
1 st term is (1)^2-1-2 = 1 -1 -2 = -2
3rd term is (3)^2-3-2 = 9-3-2=4
sum of 1st and 3rd term is -2 + 4 = 2
Answer:
B = A/5h - b; You could use
B = (A - 5hb)/5h This just puts everything over a common denominator.
Step-by-step explanation:
A = 5h (B + b) Divide both sides by 5h
A/5h = B + b Subtract b from both sides.
A/5h - b = B
Answer:
F. 2 1/9
Step-by-step explanation:
Step 1: Substitute q

When you plug in <em>n</em> = 1, 2, 3:
n(1) = 3
n(2) = 2.11111
n(3) = 2.3333
So our answer is F.
-x² + 8x - 6 = 0
x = <u>-(8) +/- √((8)² - 4(-1)(-6))</u>
2(-1)
x = <u>-8 +/- √(64 - 20)</u>
-2
x = <u>-8 +/- √(44)
</u> -2<u>
</u>x = <u>-8 +/- 2√(11)
</u> -2
x = <u>-8 + 2√(11)</u> x = <u>-8 - 2√(11)
</u> -2 -2<u>
</u>x = 4 - √(11) x = -8 + √(11)