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Assoli18 [71]
3 years ago
12

Josiah ran 4/5 mile. How many tenths are equal to 4/5 mile? Use bar diagrams to find the answer.

Mathematics
1 answer:
solmaris [256]3 years ago
8 0
Ok so u multiply the numbers by 2 since 5x2 =10 so u do that to the top num and bottom so
5x2 and 4x2 and then replace the4/5 with the answers you get
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Please help I don't understand the math language
NNADVOKAT [17]

Answer:

19

Step-by-step explanation:

3x+4 while x is 5 means (3*5)+4 so 15+4=19

If that's not what you wanted I am sorry.

8 0
2 years ago
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The function y=-5x+2 is transformed by reflecting it over the y axis. What is the equation of the new function?
vampirchik [111]

y = mx + b

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3 years ago
Please help me for 21 points.
gregori [183]

Answer:

24.44 percent

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2 years ago
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Which of the following statements is true?
bogdanovich [222]

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Step-by-step explanation:

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3 0
3 years ago
Each of 100 students in the Allen School can only take 1 CSE class each, between the four classes CSE 311, CSE 312, CSE 331, and
Naddika [18.5K]

Answer:

P(a=31,b=39,c=7,d=23) = 0.000668

Step-by-step explanation:

Sample space, n = 100

Let the number of students signed up for CSE 311 = a

Let the number of students signed up for CSE 312 = b

Let the number of students signed up for CSE 331 = c

Let the number of students signed up for CSE 332 = d

Probability of taking CSE 311, P_a = 0.3

Probability of taking CSE 312, P_b = 0.4

Probability of taking CSE 331, P_c = 0.1

Probability of taking CSE 332, P_d = 0.2

P(a,b,c,d) = \frac{n!}{a! b! c! d!} p_a^{a}  p_b^{b}  p_c^{c}  p_d^{d} \\P(a=31,b=39,c=7,d=23) = \frac{100!}{31! 39! 7! 23!} *  0.3^{31} * 0.4^{39} * 0.1^{7}  0.2^{23}\\P(a=31,b=39,c=7,d=23) = \frac{4.58*10^{111}}{2.13*10^{56}* 5040 }* (1.57*10^{-55})\\P(a=31,b=39,c=7,d=23) = 0.000668

3 0
3 years ago
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