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2 years ago

Aaaaaaaaaaa hurry please I need help Solve the following inequality and match the graph.

Mathematics

1 answer:

rusak2 [61]2 years ago

5 0

Answer:

x<4, not sure which graph it is tho, I can't see it clearly

Step-by-step explanation:

-4(-2x+8)-2x<-8

8x-32-2x<-8

8x-2x<-8+32

6x<24

x<4

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A tennis ball travels at speed of 120 miles per hour.convert this rate to feet per second

Vanyuwa [196]

$120\frac{mile}{hour}\\\\
1 \ mile=5280\ feet\\
1\ hour=3600\ seconds\\\\
120\frac{mile}{hour}=120*\frac{5280}{3600}=\frac{120*5280}{3600}=\frac{633600}{3600}=176\frac{feet}{second}\\\\
\boxed{120\frac{mile}{hour}=176\frac{feet}{second}}$

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3 years ago

The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time

cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

$1\leq t\geq \sqrt{2}$

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

$h =20-5t^{2}$ -----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height $h = 15m$

Put height value in equation 1

$15 =20-5t^{2}$

$5t^{2} =20-15$

$5t^{2} =5$

$t^{2} =1$

$t =\pm1$

We know that the time is always positive, therefore $t=1$

when the stuntman is 10m above the ground.

height $h = 10m$

Put height value in equation 1

$10 =20-5t^{2}$

$5t^{2} =20-10$

$5t^{2} =10$

$t^{2} =\frac{10}{5}$

$t^{2} =2$

$t=\pm\sqrt{2}$

$t=\sqrt{2}$

Therefore ,time interval of camera film him is $1\leq t\geq \sqrt{2}$

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Answer:

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