Question

What is the center of the circle with the equation: X2 + y2 +18x + 14y + 105 = 0

Answer 1

Answer:

(9, -7)

Step-by-step explanation:

$x^2+y^2+18x+14y+105=0$

Rearrange like x and y terms next to each other, then complete the square on both.

$(x-9)^2-361 + (y+7)^2 - 49 + 105 = 0$

The negative of the # numbers instead the brackets give you the centre of the circle.