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Korvikt [17]
3 years ago
14

What is the center of the circle with the equation: X2 + y2 +18x + 14y + 105 = 0

Mathematics
1 answer:
professor190 [17]3 years ago
8 0

Answer:

(9, -7)

Step-by-step explanation:

x^2+y^2+18x+14y+105=0\\

Rearrange like x and y terms next to each other, then complete the square on both.

(x-9)^2-361 + (y+7)^2 - 49 + 105 = 0

The negative of the # numbers instead the brackets give you the centre of the circle.

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