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Vikki [24]
3 years ago
10

The slope of a horizontal line is

Mathematics
2 answers:
Ne4ueva [31]3 years ago
6 0
The slope of the line is zero.

11111nata11111 [884]3 years ago
5 0
The slope of a horizontal line is zero
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Write an equation of the line passing through the points ( -5, -25 ),(0,0), and( 3,15)?
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Answer:

Y=5X because the slope is 5 and the Y-intercept is 0

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It is said that dogs age seven years for every people year.Masons dog,sheep,was born on masons eighth birthday.When mason was ni
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28

Step-by-step explanation:

so, if mason is 9 and the sheep is 7 year old in dog years

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3 years ago
A student spends $48 on school supplies at a store where sales tax is 7%. What is the total cost of the supplies?
Advocard [28]

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Step-by-step explanation:

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2 years ago
Read 2 more answers
Express p in terms of q if
Irina-Kira [14]

p=x^2+\dfrac{1}{x^2}\\\\p=\dfrac{x^4}{x^2}+\dfrac{1}{x^2}\\\\p=\dfrac{x^4+1}{x^2}\qquad(*)

q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}

8 0
2 years ago
before tomorrow can I have a quick answer and maybe an explanation on how to answer these kinds of questions overall? need some
MA_775_DIABLO [31]

Answer:

  a) maximum; the parabola opens downward

  b) positive; it must lie above the x-axis

  c) x = 1.5

Step-by-step explanation:

The x-intercepts of a function are the points where the graph of the function crosses the x-axis. The y-values there are zero.

The "differences" of a function are related to the average slope between adjacent points. Second differences are related to the rate of change of the slope of the function. When <em>second differences are negative</em>, as here, the slope of the quadratic function is decreasing, becoming more negative. We say the <em>curvature</em> of the function is <em>negatve</em>, and that it <em>opens downward</em>.

__

<h3>a, b.</h3>

If the graph of the parabola opens downward, and it crosses the x-axis, it must have a <em>maximum</em> that is a <em>positive value of y</em>.

__

<h3>c.</h3>

The graph of a parabola is symmetrical about its vertex. That means points on the same horizontal line are the same distance from the line of symmetry, which must go through the vertex. The x-coordinate of the vertex will be the x-coordinate of the midpoint between the two x-intercepts:

  x = (-2 +5)/2 = 3/2

The x-coordinate of the vertex is x = 1.5.

______

<em>Additional comment</em>

The attachment shows a table with three evenly-spaced points on the curve. The calculations show first differences (d1) and second differences (d2). You can see that the sign of the second diffference is negative, in agreement with the given conditions.

3 0
2 years ago
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