Answer:

Step-by-step explanation:
Given
--- interval
Required
The probability density of the volume of the cube
The volume of a cube is:

For a uniform distribution, we have:

and

implies that:

So, we have:

Solve


Recall that:

Make x the subject

So, the cumulative density is:

becomes

The CDF is:

Integrate
![F(x) = [v]\limits^{v^\frac{1}{3}}_9](https://tex.z-dn.net/?f=F%28x%29%20%3D%20%5Bv%5D%5Climits%5E%7Bv%5E%5Cfrac%7B1%7D%7B3%7D%7D_9)
Expand

The density function of the volume F(v) is:

Differentiate F(x) to give:




So:

Answer:
The slopes are

Therefore, the equations are equations of <u> Perpendicular Lines .</u>
Step-by-step explanation:
Given:
......................Equation ( 1 )
..............Equation ( 2 )
To Find:
Slope of equation 1 = ?
Slope of equation 2 = ?
Solution:
On comparing with slope point form

Where,
m = Slope
c = y-intercept
We get
Step 1.
Slope of equation 1 = m1 = 
Step 2.
Slope of equation 1 = m2 = 
Step 3.
Product of Slopes = m1 × m2 = 
Product of Slopes = m1 × m2 = -1
Which is the condition for Perpendicular Lines
The slopes are

Therefore, the equations are equations of <u> Perpendicular Lines . </u>
Answer:
Collect Like terms...Then Take the LCM
1/4x -1/3x +3 - 2
-1/12x + 1
Or
1 - 1/12x .
Option D.
Answer:
y2-y1/x2-x1 or rise/run
Step-by-step explanation:
I learned this in algebra