All categories

3 years ago

Use dimensions analysis bro convert 9 milliliters to fluid ounces.

Mathematics

1 answer:

bixtya [17]3 years ago

8 0

Answer:

I think it 1oz

Step-by-step explanation:

You might be interested in

Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

2 years ago

Please help me solve this answer it all for me please

mestny [16]

Answer:

The slopes are

$m1=\dfrac{2}{5}, m2=-\dfrac{5}{2}$

Therefore, the equations are equations of <u> Perpendicular Lines .</u>

Step-by-step explanation:

Given:

$y=\dfrac{2}{5}\times x + 1$ ......................Equation ( 1 )

$5x+2y=-4\\\\\therefore y = \dfrac{-5}{2}\times x-2$ ..............Equation ( 2 )

To Find:

Slope of equation 1 = ?

Slope of equation 2 = ?

Solution:

On comparing with slope point form

$y=mx+c$

Where,

m = Slope

c = y-intercept

We get

Step 1.

Slope of equation 1 = m1 = $\dfrac{2}{5}$

Step 2.

Slope of equation 1 = m2 = $-\dfrac{5}{2}$

Step 3.

Product of Slopes = m1 × m2 = $\dfrac{2}{5}\times -\dfrac{5}{2}=-1$

Product of Slopes = m1 × m2 = -1

Which is the condition for Perpendicular Lines

The slopes are

$m1=\dfrac{2}{5},m2=-\dfrac{5}{2}$

Therefore, the equations are equations of <u> Perpendicular Lines . </u>

4 0

2 years ago

BRAINLIESTI HAVE 10 MINS

VladimirAG [237]

Correction -125* I think

7 0

2 years ago

Which expression is equivalent to

Afina-wow [57]

Answer:

Collect Like terms...Then Take the LCM

1/4x -1/3x +3 - 2

-1/12x + 1

1 - 1/12x .

Option D.

3 0

2 years ago

How do you calculate the slope of a line?

rosijanka [135]

Answer:

y2-y1/x2-x1 or rise/run

Step-by-step explanation:

I learned this in algebra

5 0

2 years ago