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Musya8 [376]
3 years ago
13

The measures of the angles in an equilateral triangle are equal.

Mathematics
1 answer:
JulijaS [17]3 years ago
7 0

Answer:

c.60°

Step-by-step explanation:

A triangle has 3 angles. Sum of angles in a triangle is 180 degrees. Three angles of an equilateral triangle are equal

So 180/3 = 60

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Two angles are complementary. One angle is ten less than four times the other angle. Find the measure of the larger angle
Nimfa-mama [501]

Answer:

B.70

Step-by-step explanation:

For one or two angles are complementary angle(s), they have to equal 90°.

So, we need to find the larger angle, but what about the other?

Let x be the other angle and y be the angle we are looking for

x + y = 90

Lets look for x first, since one angle is ten less than four times the angle we are looking for or visa versa, we must:

y = 4x - 10

For an exchange, lets take out the y variable for another x variable:

So now we should have x + 4x - 10 = 90

Combine like terms and do cross equation :

x + 4x -10 = 90

5x - 10 = 90

Add 10 to both sides:

5x = 100

100/5 = 20

So <u><em>x=20</em></u>

<u><em></em></u>

Now for y which is what we are looking for,

y = 4x - 10

Since x is 20, plug it in

y = 80 - 10

y=70 is our larger angle

5 0
3 years ago
A speed limit of 100 kilometers per hour is approximately equal to 62mph. write an equation relating kilometers per hour to mile
aleksandr82 [10.1K]

Answer:

3

Step-by-step explanation:

IT DOES it

4 0
2 years ago
There are 5 times as many yellow labs as terriers in the dog park. if there are a total of 18 dogs, how many dogs are terriers?
gtnhenbr [62]
Terriers = x
Labs = 5x
5x + x = 18
6x = 18
6x / 6 = 18/6
x = 3
There are 3 Terriers
3 0
3 years ago
Read 2 more answers
Find the area of the parallelogram. Please this is due today. Thank you.
scZoUnD [109]
894 mi^2

as 24 x 37.25 = 894
4 0
3 years ago
Find the taylor polynomial t3(x) for the function f centered at the number
Vlad [161]
e^{-3x}=\displaystyle\sum_{n=0}^\infty\frac{(-3x)^n}{n!}=1-3x+9x^2+\cdots
\sin2x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^n(2x)^{2n+1}}{(2n+1)!}=2x-\dfrac{4x^3}3+\cdots

e^{-3x}\sin2x=\left(1-3x+9x^2+\cdots\right)\left(2x-\dfrac{4x^3}3+\cdots\right)
\approx T_3(x)=(1-3x+9x^2)\left(2x-\dfrac{4x^3}3\right)
T_3(x)=2x-6x^2+\left(18-\dfrac43\right)x^3
T_3(x)=2x-6x^2+\dfrac{50}3x^3
5 0
3 years ago
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