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Lyrx [107]
3 years ago
8

Local television news networks cover only

Computers and Technology
2 answers:
Vika [28.1K]3 years ago
3 0

Answer:

12 percent of international news

Explanation:

Just did it

loris [4]3 years ago
3 0

Answer:

12

Explanation:

You might be interested in
What is the name of the option in most presentation applications with which you can modify slide elements?
olga55 [171]

Answer:

Answer to both the question is View Master.

Explanation:

Slide Master View is an element in PowerPoint that enables one to bring modification in slides and slide layouts in the presentation applications. From this option, one is able to edit the slide master. By modifying the slide master, every slide in the presentation is affected. Using this feature, one can also modify single slide layouts.

To select Slide Master command, go to View then select the Slide Master Command, and the Slide Master view will appear on the screen.

Therefore, View Master is the correct answer.

3 0
3 years ago
Read 2 more answers
The Nigerian 4-6-9 scam refers to a fraudulent activity whereby individuals claiming to be from a foreign country will promise a
Serhud [2]

Answer:

<em>b. False</em>

<em></em>

Explanation:

<em>The system of fraud is called 4-1-9 scam</em>. And yes, victims are always promised large sum of money to secretly help in moving a large sum of money.

7 0
3 years ago
Two machines can finish a job in StartFraction 20 Over 9 EndFraction hours. Working​ alone, one machine would take one hour long
Alborosie

<em><u>Answer</u></em>

5 hours

<em><u>Explanation</u></em>

The two working together can finish a job in

\frac{20}{9}  \: hours

Also, working alone, one machine would take one hour longer than the other to complete the same job.

Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.

Their combined rate in terms of x is

\frac{1}{x}    +  \frac{1}{x - 1}

This should be equal to 20/9 hours.

\frac{1}{x}  +  \frac{1}{x - 1}  =  \frac{9}{20}

Multiply through by;

20x(x - 1) \times \frac{1}{x}  +20x(x - 1) \times   \frac{1}{x - 1}  =  20x(x - 1) \times \frac{9}{0}

20(x - 1)  +20x = 9x(x - 1)

20x - 20+20x = 9{x}^{2}  - 9x

9{x}^{2}  - 9x - 20x - 20x + 20= 0

9{x}^{2}  - 49x  + 20= 0

Factor to get:

(9x - 4)(x - 5) = 0

x =  \frac{4}{9}  \: or \: x = 5

It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.

Therefore the slower finish in 5 hours.

8 0
3 years ago
Which scenario is most likely due to an everyday problem rather than a
tester [92]

The scenario is most likely due to an everyday problem rather than cultural difference among people collaborating online is option D. A team member's bandwidth is limited, and the video feed keeps freezing.

<h3>What is collaborating online?</h3>

Online collaboration is known to be a term that connote the use the internet as well as other forms of online tools to be able to work together on some work or project.

Note that it is one that is done Instead of a person sitting in a physical office space, the online collaboration gives room for employees to be able to work together from different locations and tech by accessing the virtual work environments as well as other shared online workspaces.

Therefore, The scenario is most likely due to an everyday problem rather than cultural difference among people collaborating online is option D. A team member's bandwidth is limited, and the video feed keeps freezing.

Learn more about collaborating online from

brainly.com/question/514815

#SPJ1

6 0
1 year ago
Hello everyone. I need help. C programming. Create at least two more functions except the main () function to collect them.
Andrew [12]

Answer:

Explanation:

#include <iostream>

using namespace std;

int costdays(int);

int costhrs(int,int);

int main()

{

   int dd,hh,mm,tmph,tmpd,tmpm=0;

   int pcost,mcost=0;

   cout<<"Enter Parking time" << endl;

   cout<<"Hours: ";

   cin>>hh;

   cout<<"Minutes: ";

   cin>>mm;

   

   if (mm>60)

   {

       tmph=mm/60;

       hh+=tmph;

       mm-=(tmph*60);

   }

   if (hh>24)

   {

       tmpd=hh/24;

       dd+=tmpd;

       hh-=(tmpd*24);

   }

   if ((hh>4)&&(mm>0))

   {

       pcost+=costdays(1);

   }

   else

   {

       mcost=costhrs(hh,mm);

   }

   cout<<"Total time: ";

   if (dd>0)

   {

       cout<<dd<<"days ";

       pcost+=costdays(dd);

   }

   pcost+=mcost;

   cout<<hh<<"h "<<mm<<"mins"<<endl;

   cout<<"Total Cost :"<<pcost<<"Won";

   return 0;

}

int costdays(int dd)

{

   return(dd*25000);

}

int costhrs(int hh,int mm)

{

   int tmpm, tmp=0;

   tmp=(hh*6)*1000;

   tmp+=(mm/10)*1000;

   tmpm=mm-((mm/10)*10);

   if (tmpm>0)

   {

       tmp+=1000;

   }

   return(tmp);

}

3 0
3 years ago
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