Answer:
16
Step-by-step explanation:
Put the numbers where the variables are and evaluate:
F(3) = 2(3)^2 +1 = 19
G(4) = 2(4) -1 = 7
H(5) = 5
Then the desired sum is ...
F(3) +G(4) -2H(5) = 19 +7 -2(5) = 16
Answer:
0.95
(Don't have paper, because I accidentally threw away paper )
Hope this helps!
1,366-1,366
This is = to 0
1. 8b+40
2. -36n+16
3. -6y-3
4. 4k+32
5. 3n^2 (squared)
The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
Given that,
The function is (-x+3)/ (3x-2)
We have to find f(1) and f'(x).
Take the function expression
f(x)= (-x+3)/ (3x-2)
Taking x as 1 value
f(1)= (-1+3)/(3(1)-2)
f(1)=2/1
f(1)=1
Now, to get f'(x)
With regard to x, we must differentiate.
f(x) is in u/v
We know
u/v=(vu'-uv')/ v² (formula)
f'(x)= ((3x-2)(-1)- (-x+3)(3))/ (3x-2)²
f'(x)= ((-3x+2)-(-3x+9))/ 9x²- 12x+4
f'(x)=(-3x+2+3x-9)/ 9x²- 12x+4
f'(x)=2-9/ (9x²- 12x+4)
f'(x)=-7/ (9x²- 12x+4)
Therefore, The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
To learn more about function visit: brainly.com/question/14002287
#SPJ1
