Answer:
I found two different solutions. Hope one of them help!
1. x = -1/3 = -0.333
2. x = 5/2 = 2.500
Step-by-step explanation:
13 ± √ 289
x = ——————
12
Can √ 289 be simplified ?
Yes! The prime factorization of 289 is
17•17
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 289 = √ 17•17 =
± 17 • √ 1 =
± 17
So now we are looking at:
x = ( 13 ± 17) / 12
Two real solutions:
x =(13+√289)/12=(13+17)/12= 2.500
or
x =(13-√289)/12=(13-17)/12= -0.333
Two solutions were found :
x = -1/3 = -0.333
x = 5/2 = 2.500
Use Multiplication Distribute Property: (xy)^a = x^ay^a
6^2(x^-2)^2(0.5x)^4
Simplify 6^2 to 36
36(x^-2)^2(0.5x)^4
Use this rule: (x^a)^b = x^ab
36x^-4(0.5x)^4
Use the Negative Power Rule: x^-a = 1/x^a
36 × 1/x^4(0.5x)^4
Use the Multiplication Distributive Property: (xy)^a = x^ay^a
36 × 1/x^4 × 0.5^4x^4
Simplify 0.5^4 to 0.0625
36 × 1/x^4 × 0.0625x^4
Simplify
2.25x^4/x^4
Cancel x^4
<u>2.25</u>
Applying or Pythagorean theorem, as determined by x indicated em um dos retângulos each Triangles. What do u mean
Answer:
n ≈ 3
Step-by-step explanation:
9n-2<7+20
<span>You are given the waiting times between a subway departure schedule and the arrival of a passenger that are uniformly distributed between 0 and 6 minutes. You are asked to find the probability that a randomly selected passenger has a waiting time greater than 3.25 minutes.
Le us denote P as the probability that the randomly selected passenger has a waiting time greater than 3.25 minutes.
P = (length of the shaded region) x (height of the shaded region)
P = (6 - 3.25) * (0.167)
P = 2.75 * 0.167
P = 0.40915
P = 0.41</span><span />
