All categories

4 years ago

The sum of two numbers is 53 and the difference is 15 . What are the numbers?

Mathematics

2 answers:

Stells [14]4 years ago

6 0

Answer:

34 and 19.

Step-by-step explanation:

Since the sum of the two numbers is 53, x+y=53. Since the difference is 15, x-y=15.

Adding x+y=53

and x-y=15,

The ys cancel, leaving 2x=68, or x=34. Therefore, 34-y=15, or y=19.

cluponka [151]4 years ago

3 0

Answer:

34 and 19.

Step-by-step explanation:

If the numbers are x and y:

x + y = 53

x - y = 15 Add the 2 equations:

2x + y - y = 68

2x = 68

x = 34.

As they add up to 53:

y = 53 - 34 = 19.

You might be interested in

Select the TWO correct statements. The product of 3/5 and 4 is greater than 4. The product of 3/5 and 4 is less than 3/5. The pr

Musya8 [376]

Answer:

the product of 11/2 and 2 is greater than 11/2

The product of 13/4 and 5/2 is greater than 13/4

Step-by-step explanation:

11/2 * 2 = 11

13/4 * 5/2 = 8.125

3 0

4 years ago

Why do you think a quadratic always becomes a positive number?

Alenkasestr [34]

Answer:

Step-by-step explanation:

If a and (b - c^9/a) are both positive or both negatives, the quadratic will be either, always positive or negative.they are not both then, quadratic will be be positive for some values and negative for others.

7 0

3 years ago

Disproof by counter example: For all positive integers x: 1/x < 1

xz_007 [3.2K]

Answer:

The given statement is correct for all positive integers.

Step-by-step explanation:

The given inequality is

$\frac{1}{x}$ for all positive integers

$\frac{1}{x}1$

5 0

3 years ago

Which of the following has a slope of –2 and a y-intercept of 4?

Mumz [18]

The coefficient of x is the value for slope in y-intercept form, and the number that we add or subtract is our y-intercept. So in this case, we want to look for a "-2" in front of x and a +4 in the equation.
Answer choice A fulfills those conditions. (I am also assuming that answer choice A should have had an x in it, but you accidentally forgot to type it.)

Please rate & heart answers you find helpful! :)

6 0

3 years ago

Suppose f(x, y) is a differentiable function of x and y and let g(r, s) = f (2rs, 8s − 2r). Use

worty [1.4K]

By the chain rule,

$\dfrac{\partial g}{\partial r} = \dfrac{\partial f}{\partial r} \\\\ ~~~~~ = \dfrac{\partial f}{\partial x} \dfrac{\partial x}{\partial r} + \dfrac{\partial f}{\partial y} \dfrac{\partial y}{\partial r} \\\\ ~~~~~ = 2 s \dfrac{\partial f}{\partial x} - 2 \dfrac{\partial f}{\partial y}$