Answer:

Step-by-step explanation:
Given:

Solve:








![\mathrm{For\:}u^n\: > \:a\mathrm{,\:if\:}n\:\mathrm{is\:even}\mathrm{\:then\:}u\: < \:-\sqrt[n]{a}\:or\:u\: > \:\sqrt[n]{a}](https://tex.z-dn.net/?f=%5Cmathrm%7BFor%5C%3A%7Du%5En%5C%3A%20%3E%20%5C%3Aa%5Cmathrm%7B%2C%5C%3Aif%5C%3A%7Dn%5C%3A%5Cmathrm%7Bis%5C%3Aeven%7D%5Cmathrm%7B%5C%3Athen%5C%3A%7Du%5C%3A%20%3C%20%5C%3A-%5Csqrt%5Bn%5D%7Ba%7D%5C%3Aor%5C%3Au%5C%3A%20%3E%20%5C%3A%5Csqrt%5Bn%5D%7Ba%7D)



<u><em>~lenvy~</em></u>
ANSWER: 28
EXPLANATION:
Area is l • w or length • width. We know the width is 7 but for the length you only multiply the straight line. As 5 is slanted we use 4 instead, leaving us to multiply 7 • 4. This give us a solution of 28.
Hope that helps★
Answer:
Yes there is i know ots quora
Answer:
1
Step-by-step explanation:
Look at the LHS: you have the square of x, then you have 2 times x, times -1. to complete a square you just need to add the square of -1, that is 1. That becomes

I don't understand the question