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Tatiana [17]
3 years ago
7

How many 9s are there in 63? .

Mathematics
2 answers:
bixtya [17]3 years ago
4 0

Answer:

7

Step-by-step explanation:

63 ÷ 9 = 7

garri49 [273]3 years ago
4 0
9*7=63 7*9=63 that’s the answer
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Midpoint of the line segment (-1,6), (-6,5)
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The answer is:

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<u>Picture 1:</u>

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Another way to see how this is correct is to notice that the x is multiplying by 9 to get y. It works out as you look at it and plug it in!

<u>Picture 2:</u>

Yes, this is a proportional relationship. Since Dennis is adding 3 logs every hour, it is keeping a consistent pattern.

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5 0
3 years ago
Write a function rule for the table.
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7 0
3 years ago
Read 2 more answers
In ΔOPQ, the measure of ∠Q=90°, the measure of ∠O=26°, and QO = 4.9 feet. Find the length of PQ to the nearest tenth of a foot.
Step2247 [10]

Given:

In ΔOPQ, m∠Q=90°, m∠O=26°, and QO = 4.9 feet.

To find:

The measure of side PQ.

Solution:

In ΔOPQ,

m\angle O+m\angle P+m\angle Q=180^\circ        [Angle sum property]

26^\circ+m\angle P+90^\circ=180^\circ

m\angle P+116^\circ=180^\circ

m\angle P=180^\circ -116^\circ

m\angle P=64^\circ

According to Law of Sines, we get

\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}

Using the Law of Sines, we get

\dfrac{p}{\sin P}=\dfrac{o}{\sin O}

\dfrac{QO}{\sin P}=\dfrac{PQ}{\sin O}

Substituting the given values, we get

\dfrac{4.9}{\sin (64^\circ)}=\dfrac{PQ}{\sin (26^\circ)}

\dfrac{4.9}{0.89879}=\dfrac{PQ}{0.43837}

\dfrac{4.9}{0.89879}\times 0.43837=PQ

2.38989=PQ

Approximate the value to the nearest tenth of a foot.

PQ\approx 2.4

Therefore, the length of PQ is 2.4 ft.

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3 years ago
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