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andriy [413]
3 years ago
9

The sign of the value of cos 112.5º is _____?

Mathematics
1 answer:
brilliants [131]3 years ago
4 0
Hello,
<span>using double angle formulas:
</span><span>cos 112.5º= cos (225/2)º= -√[(1+cos 225º)/2)];

1+cos 225º=1-√2/2=(2-√2)/2
(1+cos 225º)/2)=(2-√2)/4
-√[(1+cos 225º)/2)]=-√(2-√2)/2
cos 112.5º=-√(2-√2)/2</span>
bye :-)
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For ​f(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B5%7D%20-4" id="TexFormula1" title="\sqrt{x+5} -4" alt="\sqrt{x+5} -4
ira [324]

Answer:

\\ (f+g)(x)=f(x)+g(x)=\sqrt{x+5}-4+\sqrt{x+5}+4=2\sqrt{x+5}

7 0
2 years ago
Can someone explain this.
natta225 [31]

Answer:

No

Step-by-step explanation:

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6 0
2 years ago
Please solve this<br> dont give stupid answer for credit.....
mart [117]

(i)

∠BAD + ∠ABD + ∠ADB = 180 <em>the sum of the angles of a triangle equals 180°</em>

70 + 50 + ∠ADB = 180 <em>substituted given information</em>

∠ADB = 60 <em>subtraction property (subtracted 70 and 50)</em>

∠ABD + ∠BDC = ∠ADC <em>angle addition property</em>

60 + ∠BDC = 80 <em>substituted solved and given information</em>

∠BDC = 20 <em>subtraction property</em>

(ii) SORRY but I'm not sure how to find ∠BCD. If ∠ADC = ∠ABC, then ∠DBC = 30. We already calculated ∠BDC = 20, which means that ∠BCD = 130

(iii)

∠BCA = ∠ADB <em>given as a hint</em>

∠BCA = 60 <em>substituted ∠ADB that was solved in part (i)</em>

Answer: (i) = 20, (ii) = 130?, (iii) = 60

6 0
3 years ago
Rewrite f(x) = x^2 + 4x -12 in the form that would most easily help you identify
ANEK [815]

Answer:

A.  f(x)=(x+6)(x-2)

Step-by-step explanation:

Given function:

f(x)=x^2+4x-12

To rewrite the equation such that the zeros of the function can be easily identified.

Solution:

In order to find the zeros of the given quadratic function, we will use factorization by splitting up the middle term.

We have:

f(x)=x^2+4x-12

Splitting 4x into two term such that the sum of the two terms = 4x(middle term) and the product of the two terms is =-12x^2 (product of first and last term)

The terms are  6x,-2x as their sum = 4x and their product = -12x^2

So, we have:

f(x)=x^2+6x-2x-12

Factoring in pairs of first two terms and last two terms by factoring out their G.C.F.

f(x)=x(x+6)-2(x+6)

Since (x+6) is a common term, we can factor it out further.

f(x)=(x+6)(x-2)  (Answer)

From the above function, we can identify that the zeros of the function are -6 and 2.

4 0
2 years ago
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Answer:

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Step-by-step explanation:

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