Answer:
x = 6
y = 9
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15÷8=1.875
I would round up to $1.88 /cookie.
First you would solve for h(5) by plugging in 5 as your x, then solving it.
h(5) = 5^2 + 1
h(5) = 25 + 1
h(5) = 26
Next you would multiply the 26 by the individual h, which is basically h(1).
h(1) = 1^2 + 1
h(1) = 2
Lastly you multiply your h(1) value by the h(5) value to get your answer.
h(1) • h(5) = 26 • 2
h[h(5)] = 52
Given:
Vertex ===> (h, k) (2, 4)
The parabola passes through the point: (x, y) ==> (3, 6)
Let's find the equation of a parabola.
To find the equation, use the general equation of a parabola with vertex (h, k):

Where:
(h, k) ==> (2, 4)
(x, y) ==> (3, 6)
Substitute values into the general equation:

Subtract 4 from both sides:

Substitute 2 for a, and input the values of the vertex (h, k) in the general vertex equation:

Therefore, the equation of the parabola is:

ANSWER:
The valid conclusions for the manager based on the considered test is given by: Option
<h3>When do we perform one sample z-test?</h3>
One sample z-test is performed if the sample size is large enough (n > 30) and we want to know if the sample comes from the specific population.
For this case, we're specified that:
- Population mean =
= $150 - Population standard deviation =
= $30.20 - Sample mean =
= $160 - Sample size = n = 40 > 30
- Level of significance =
= 2.5% = 0.025 - We want to determine if the average customer spends more in his store than the national average.
Forming hypotheses:
- Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get:

- Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically

where
is the hypothesized population mean of the money his customer spends in his store.
The z-test statistic we get is:

The test is single tailed, (right tailed).
The critical value of z at level of significance 0.025 is 1.96
Since we've got 2.904 > 1.96, so we reject the null hypothesis.
(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).
Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.
Learn more about one-sample z-test here:
brainly.com/question/21477856