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3 years ago

5

Please help! Correct answer only, please! I've been stuck on this assignment since yesterday, and I don't want to lose any more

points.
Trudy has a collection of 11 dice, 4 of which have twelve sides.
If Trudy randomly rolls 4 dice in a specific order, what is the probability that just the first 2 of the chosen dice have twelve sides?

Write your answer as a decimal rounded to four decimal places.

1 answer:

uranmaximum [27]3 years ago

6 0

Answer:

Approximately 0.0364

Idk if this is right... :(

Step-by-step explanation:

4 dice with 12 sides

7 dice without 121 sides.

There is a $\frac{4}{11}$ chance that the first dice has 12 sides.

There is a $\frac{3}{10}$ chance that the second dice has 12 sides.

There is a $\frac{7}{9}$ chance that the third dice doesn't have 12 sides.

There is a $\frac{3}{4}$ chance that the fourth dice doesn't have 12 sides.

Multiply them up:

$\frac{4}{11}*\frac{3}{10}*\frac{7}{9}*\frac{3}{4}=\frac{252}{3960}=0.0363636363636...$

So approximately 0.0364

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Which side lengths form a triangle that is similar to triangle ABC

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A.
10x3=30
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7x3=21
All sides have increased in size by 3 times.

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4 years ago

Help plz I really need help thx

blondinia [14]

D. 133*1.285=171 pennies in the jar

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3 years ago

Read 2 more answers

At 8am,Ming Wei started travelling from Town A to Town B.At 8:40am, Ali started travelling from Town B to Town A.Mingwei's speed

Vesnalui [34]

Let's write some equations.

Mingwei's distance from Town A after $x$ hours from 8:00 is $45x$ .

Ali's distance from Town B after $x$ hours is $30x-20$ , since he doesn't start walking for 40 minutes.

When Mingwei's distance is twice Ali's, they've met up (since their distance from Town A is twice their distance from Town B).

So, this gives $45x=60x-40$ , so $15x=40$ , so $x=\frac{40}{15} = \frac{8}{3}$ , so the time is 10:40.

After $\frac83$ hours, Mingwei has traveled $45 * 8 / 3 = 120$ kilometers while Ali has traveled sixty, so the distance between the towns is $180$ kilometers.

7 0

3 years ago

The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1

Aleksandr-060686 [28]

Answer:

a) The probability that a student has either a Visa card or a MasterCard is 0.71.

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b) In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards is $P(V \cap M)=0.03$

a) Probability that a student has either a Visa card or a Master Card is given by,

$P(V \cup M) = P(V) + P(M) - P(V\cap M)$

$P(V \cup M) = 0.63+ 0.11- 0.03$

$P(V \cup M) =0.74- 0.03$

$P(V \cup M) =0.71$

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if $P(A\cap B)=P(A)P(B)$

For V and M to be independent the condition is satisfied,

$P(V\cap M)=P(V)P(M)$

Substitute the values,

$0.03=0.63\times 0.11$

$0.03\neq 0.0693$

So, V and M are not independent.

6 0

3 years ago

The cosine of 23° is equivalent to the sine of what angle

Archy [21]

Answer:

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

(There are more values since we can go around the circle from 67 degrees numerous times.)

Step-by-step explanation:

You can use a co-function identity.

The co-function of sine is cosine just like the co-function of cosine is sine.

Notice that cosine is co-(sine).

Anyways co-functions have this identity:

$\cos(90^\circ-x)=\sin(x)$

or

$\sin(90^\circ-x)=\cos(x)$

You can prove those drawing a right triangle.

I drew a triangle in my picture just so I can have something to reference proving both of the identities I just wrote:

The sum of the angles is 180.

So 90+x+(missing angle)=180.

Let's solve for the missing angle.

Subtract 90 on both sides:

x+(missing angle)=90

Subtract x on both sides:

(missing angle)=90-x.

So the missing angle has measurement (90-x).

So cos(90-x)=a/c

and sin(x)=a/c.

Since cos(90-x) and sin(x) have the same value of a/c, then one can conclude that cos(90-x)=sin(x).

We can do this also for cos(x) and sin(90-x).

cos(x)=b/c

sin(90-x)=b/c

This means sin(90-x)=cos(x).

So back to the problem:

cos(23)=sin(90-23)

cos(23)=sin(67)

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

6 0

3 years ago