Answer:
B=![\left[\begin{array}{ccc}0&0\\0&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Let's do the multiplication AB.
If A=![\left[\begin{array}{ccc}1&0\\0&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
then the first row of A is= (1 0) by the first column of B= (0 0) is equal to zero.
the first row of A is= (1 0) by the second column of B= (0 1) is equal to zero too because 1.0+0.1=0.
the second row of A is= (0 0) by any colum of B is equal to zero too.
So we have found an example that works!
Answer:
- D. l = 3 || 4 < c < y || 8l + 7.5c ≥ 70
Step-by-step explanation:
<h3>Work at library</h3>
- Time = 3 hours ⇒ l = 3
- Payment = $8 per hour
- Total payment = 8l
<h3>Work at coffee shop</h3>
- Time = between 4 and 7 hours ⇒ 4 < c < 7
- Payment = $7.5 per hour
- Total payment = 7.5c
Target income = at least $70 daily
<u>So the system as per above parameters:</u>
- l = 3
- 4 < c < y
- 8l + 7.5c ≥ 70
Correct option is D
Answer:
each unit being divided into smaller parts
Step-by-step explanation:
That would be 1/2 divided by 3
Its A
Answer:
z + 12 = 9
Reorder the terms:
12 + z = 9
Solving
12 + z = 9
Solving for variable 'z'.
Move all terms containing z to the left, all other terms to the right.
Add '-12' to each side of the equation.
12 + -12 + z = 9 + -12
Combine like terms: 12 + -12 = 0
0 + z = 9 + -12
z = 9 + -12
Combine like terms: 9 + -12 = -3
z = -3
Simplifying
z = -3
Step-by-step explanation:
