I will assume that we are trying to find the slope between (-9,2) and (9, 2)
The slope's equation ⇒ ![\frac{y2-y1}{x2-x1}](https://tex.z-dn.net/?f=%5Cfrac%7By2-y1%7D%7Bx2-x1%7D)
<u>Let's set the variables</u>:
(x1, y1) --> (-9, 2)
(x2, y2) --> (9, 2)
<u>Now let's plug them in:</u>
![Slope = \frac{2-2}{9--9} =\frac{0}{18} =0](https://tex.z-dn.net/?f=Slope%20%3D%20%5Cfrac%7B2-2%7D%7B9--9%7D%20%3D%5Cfrac%7B0%7D%7B18%7D%20%3D0)
<u>Thus the slope of the line is 0.</u>
Hope that helps!
ANSWER
![x + y + 2 = 0](https://tex.z-dn.net/?f=x%20%2B%20y%20%2B%202%20%3D%200)
EXPLANATION
The given line passes through;
(-1,-1) and it is parallel to x + y = 3.
This line given to us can be rewritten as
y=-x+1
It has slope m=-1.
The line parallel to this line also has slope m=-1.
We obtain the equation of the line using the formula:
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
We substitute the slope and the point to obtain:
![y - - 1 = - 1(x - - 1)](https://tex.z-dn.net/?f=y%20-%20%20-%201%20%3D%20%20-%201%28x%20-%20%20-%201%29)
![y + 1 = - 1(x + 1)](https://tex.z-dn.net/?f=y%20%2B%201%20%3D%20%20-%201%28x%20%2B%201%29)
![y = - x - 1 - 1](https://tex.z-dn.net/?f=y%20%3D%20%20-%20x%20-%201%20-%201)
The equation of the line is
![x + y + 2 = 0](https://tex.z-dn.net/?f=x%20%2B%20y%20%2B%202%20%3D%200)
Step-by-step explanation:
Let us assume that 1/2+root 3 is rational . So 1/2+root 3 = a/b where a and b are irrationals. since rhs is a rational number root 3 should be also rational .
Answer:
Step-by-step explanation:
semi circle: pi(r^2)/ 2
r=3
AREA: 14.14