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mash [69]
3 years ago
14

F(x)=-2x+3 how do you find x if f(x) = 11

Mathematics
1 answer:
NeX [460]3 years ago
5 0
Since we know f(x)=11 all we need to do is substitute and solve. so
11=-2x+3 subtract 3 from both sides
8=-2x divide both sides by -2
-4=x
sub back in to check

-2(-4)+3=8+3=11 looks good
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What type of number is this?<br>0.707070...​
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Answer:

A repeating decimal...

Step-by-step explanation:

Because the numbers after the decimal points keep repeating.

4 0
3 years ago
What is the square root of four
postnew [5]
The square root of four is two
4 0
2 years ago
Ted needs an average of at least 70 on his three history tests. He has already scored 85 and 60 on two tests. What is the minimu
baherus [9]
He must get a 65 as a minimum grade on his third test to get an average of 70.
Equation is
                       85 + 60 + x
                     ------------------- greater than or equal to 70
                              3
3 0
3 years ago
How do I do this qn?
denis-greek [22]
You can take the log of the left and right hand side, and then apply the <span>logarithm rules:

log(a</span>ˣ) = x·log(a)
log(ab) = log(a) + log(b)

log(9^(x-1) * 2^(2x+2)) = log(6^(3x))
log(9^(x-1)) + log(2^(2x+2)) = 3x log(6)
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x(log9 + 2log2 - 3log6) = log9 - 2log2
x = (log9 - 2log2) / (log9 + 2log2 - 3log6)

simplifying by writing log9 = 2log3 and log6 = log2+log3

x= 2(log3 - log2) / (2log3 + 2log2 - 3log2 - 3log3) = 
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3 0
3 years ago
Factoring Quadratic Trinomials 6n^2 - n - 40 =
Sophie [7]

Answer:

(3n - 8)(2n + 5)

Step-by-step explanation:

6n² - n - 40

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product = 6 × - 40 = - 240 and sum = - 1

The factors are - 16 and + 15

Use these factors to split the n- term

6n² - 16n + 15n - 40 ( factor the first/second and third/fourth terms )

2n(3n - 8) + 5(3n - 8) ← factor out (3n - 8) from each term

(3n - 8)(2n + 5)

Then

6n² - n - 40 = (3n - 8)(2n + 5)

6 0
2 years ago
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