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3 years ago

F(x)=-2x+3 how do you find x if f(x) = 11

1 answer:

5 0

Since we know f(x)=11 all we need to do is substitute and solve. so
11=-2x+3 subtract 3 from both sides
8=-2x divide both sides by -2
-4=x
sub back in to check

-2(-4)+3=8+3=11 looks good

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2 years ago

Which equation represents a line that passes through (-2, 4) and has a slope of 1/2?

jok3333 [9.3K]

Answer:

$\large\boxed{y-4=\dfrac{1}{2}(x+2)\text{- point-slope form}}\\\boxed{y=\dfrac{1}{2}x+5\text{- slope-intercept form}}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

We have the slope $m=\dfrac{1}{2}$ and the point $(-2, 4)$ .

Substitute:

$y-4=\dfrac{1}{2}(x-(-2))$

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Convert to the slope-intercept form (y = mx + b):

$y-4=\dfrac{1}{2}(x+2)$ <em> use the distributive property</em>

$y-4=\dfrac{1}{2}x+1$ <em>add 4 to both sides</em>

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2 years ago

Given h(x) = -x+5, solve for x when h(x) =0

Vedmedyk [2.9K]

Answer:

x=1

Step-by-step explanation:

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3 years ago

What is y= 4^x with the domain of (-2,0,3)

Elena L [17]

Step-by-step explanation:

$\text{Put}\ x=-2,\ x=0\ \text{and}\ x=3\ \text{to the equation}\ y=4^x:\\\\y=4^{-2}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\y=\dfrac{1}{4^2}=\dfrac{1}{16}\\-----------------\\\\y=4^0=1\\-----------------\\\\y=4^3=64$

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