Answer:
(A) The slope of secant line is 18.
(B) The slope of secant line is h+16.
Step-by-step explanation:
(A)
The given function is

At x=3,

At x=9,

The secant line joining (3,27) and (9,135). So, the slope of secant line is


The slope of secant line is 18.
(B)
The given function is

At x=5,

At x=5+h,

The secant line joining (5,55) and
. So, the slope of secant line is



The slope of secant line is h+16.
Step-by-step explanation:
The sum of ages of two friends is 13 years.
The product of their ages is 42.
<em>Let the age of 1st friend and 2nd friend is x, y respectively.</em>
<em>1 st condition= The sum of ages of two friends is 13 y</em><em>r</em><em>s. </em>
i.e x+y = 13........ (I)
<em>2nd condition= The product of their ages is 42.</em>
i.e X*y = 42........(ii)
From equation (I)
X+y = 13
or, X = 13-y........ (iii)
<em>Putting the equation (iii) in equation (ii).</em>
X*y= 42
(13-y) * y = 42
13y - y^2 = 42





Either; y-6 = 0
y = 6
Or;
y-7=0
y = 7
<em>Keeping the value of y as "7" in equation (ii)</em>
x*y = 42
7x = 42
X = 42/7
Therefore, the value of X is 6.
Therefore, either 1st friend is 6 years and 2nd is 7 years.
<em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>it </u></em><em><u>helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Think of sea level as 0 on number line
-13 + 6 - 15
Answer:−3+3=−4
2+3−=15
4−3−=19
2 3
Step 1: Pair the equations to eliminate y because the y terms are already additive inverses
1
−3+3=−4
2+3−=15
2
2+3−=15
4−3−=19
2 3 4
3 =11
5
6 −2=34
Step 2: Write the two new equations
as a system
Step 3: Substitute the value for x and z
into one of the original equations
3 =11
3 5 +2=11
4
5−3+3 −2 =−4
15+2=11
5
6 −2=34
5−3−6=−4
−3−1=−4
9x
2=−4
=−2
= 45
x = 5
−3=−3
=1
The solution (5, 1, -2)
Step-by-step explanation:
4x-7x= 13
⇒ -3x= 13
⇒ x= 13/(-3)
⇒ x= -13/3
The final answer is x= -13/3~