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3 years ago

Two data sets are summarized in the box plots shown.

Mathematics

1 answer:

Akimi4 [234]3 years ago

4 0

Answer: A,D

Step-by-step explanation:

I took the test

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Is –2 − –39 positive or negative?

pochemuha

Answer:

Positive 37

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Select the correct answer.

ratelena [41]

Answer:

A. $x(x+12) -7(x+12)$

Step-by-step explanation:

Factoring is the process of taking common terms out of an expression such that one can represent the expression as the result of smaller values. When given the following expression:

$x^2 +5x - 84$

First, represent the linear term as the sum of two terms such that each term shares a common factor with the other terms in the expression.

$x^2 +12x - 7x - 84$

Now take out the common factors,

$x(x+12) -7(x+12)$

Thus, the correct option is choice (A).

5 0

3 years ago

Findℒ{f(t)}by first using a trigonometric identity. (Write your answer as a function of s.)f(t) = 12 cost −π6

allsm [11]

Answer:

$L(f(t)) = \dfrac{6}{S^2+1} [\sqrt{3} \ S +1 ]$

Step-by-step explanation:

Given that:

$f(t) = 12 cos (t- \dfrac{\pi}{6})$

recall that:

cos (A-B) = cos AcosB + sin A sin B

∴

$f(t) = 12 [cos\ t \ cos \dfrac{\pi}{6}+ sin \ t \ sin \dfrac{\pi}{6}]$

$f(t) = 12 [cos \ t \ \dfrac{3}{2}+ sin \ t \ sin \dfrac{1}{2}]$

$f(t) = 6 \sqrt{3} \ cos \ (t) + 6 \ sin \ (t)$

$L(f(t)) = L ( 6 \sqrt{3} \ cos \ (t) + 6 \ sin \ (t) ]$

$L(f(t)) = 6 \sqrt{3} \ L [cos \ (t) ] + 6\ L [ sin \ (t) ]$

$L(f(t)) = 6 \sqrt{3} \dfrac{S}{S^2 + 1^2}+ 6 \dfrac{1}{S^2 +1^2}$

$L(f(t)) = \dfrac{6 \sqrt{3} +6 }{S^2+1}$

$L(f(t)) = \dfrac{6( \sqrt{3} \ S +1 }{S^2+1}$

$L(f(t)) = \dfrac{6}{S^2+1} [\sqrt{3} \ S +1 ]$

7 0

3 years ago

(a) Let {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it app

Nataliya [291]

Answer:

0.625

Step-by-step explanation:

Given that {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it applies to the partition {A1, A2} and the event B.

Since A1 and A2 are mutually exclusive and exhaustive, we can say

b) P(B) = P(A1B)+P(A2B)

Selecting any one coin is having probability 0.50. and A1, A2 are events that the coins show heads. $P(B/A1) = 0.50 \\P(B/A2) = 0.75\\P(A1B) = 0.5(0.5) = 0.25 \\P(A2B) = 0.75(0.5) = 0.375\\P(B) = 0.625$