You can set up a system of equations for this problem. x= number of coach tickets and y = number of first class tickets.
$210x + $1200y = $10,230 (cost of coach ticket plus cost of first class tickets is total budget)
x + y = 11 (number of coach tickets plus number of first class tickets is total number of people)
Solve the second equation for y to get y = 11 - x, then plug that into the first equation and solve for x:
$210x + $1200(11 - x) = $10,230
$210x + $13,200 - $1200x = $10,230
-$990x + $13,200 = $10,230
-$990x = $2,970
x = 3
Sarah bought x = 3 coach tickets. Plug that into the second equation and solve for y:
3 + y = 11
y = 8
Sarah bought y = 8 first class tickets.
Answer:
Step-by-step explanation:
simplify (5-3)
PEMDAS= parentheses- e -MULTIPLY- DIVIDE - ADD- SUBTRACT
2(5-3)2+62
(2*2)2+62
8+62
70
The difference is -10 because
9-10= 1
-1-10= -11
-11-10= -21
common difference means you add and common ratios means you multiply.
hope this helps!
Answer: 23.2
Step-by-step explanation:
