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SVEN [57.7K]
4 years ago
8

What is the smallest integer that can be added to -2m3 − m + m2 + 1 to make it completely divisible by m + 1

Mathematics
1 answer:
tia_tia [17]4 years ago
8 0
When divided by 2 we get perfect square 
<span>(2^n * 3^m) / 2 = 2^(n-1) * 3^m is a perfect square </span>
(n-1) and m are divisible by 2
 <span>When divided by 3 we get perfect cube </span>
<span>(2^n * 3^m) / 3 = 2^n * 3^(m-1) is a perfect cube </span>
n and (m-1) are divisible by 3 
<span>(n-1) divisible by 2 & n divisible by 3 → n = 3 </span>
<span>m divisible by 2 & (m-1) divisible by 3 → m = 4 
</span><span>Number = 2³ * 3⁴ = 648 
</span>648/2 = 324 = 18² 
<span>648/3 = 216 = 6³ 
</span>ANSWER: 648
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4 years ago
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Anon25 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

f\left(x\right)=\sqrt{x^3-16x}

We know that the domain of the function is the set of input or arguments for which the function is real and defined.  

In other words,  

  • Domain refers to all the possible sets of input values on the x-axis.

Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.

x^3-16x\ge 0

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\left(x+4\right)\left(x-4\right)\ge \:0

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-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4

Thus,

The domain of the function f(x) is:

x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}

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3 years ago
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vlabodo [156]

Answer:

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