The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) us
2 answers:
Answer:
When Harold wrote his equation, the point he used was (7,0).
Step-by-step explanation:
The equation of a linear function in point-slope form :
--A
Where m is the slope
are passing points
Harold's Equation :
On comparing Harold's Equation with A
Thus the passing point is (7,0).
Hence Option C is correct.
When Harold wrote his equation, the point he used was (7,0).
You might be interested in
The solution to this system is (x, y) = (8, -22).
The y-values get closer together by 2 units for each 2-unit increase in x. The difference at x=2 is 6, so we expect the difference in y-values to be zero when we increase x by 6 (from 2 to 8).
You can extend each table after the same pattern.
In table 1, x-values increase by 2 and y-values decrease by 8.
In table 2, x-values increase by 2 and y-values decrease by 6.
The attachment shows the tables extended to x=10. We note that the y-values are the same (-22) for x=8 (as we predicted above). That means the solution is ...
... (x, y) = (8, -22)
