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GuDViN [60]
3 years ago
15

The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) us

ing a point and the slope. Which point did Harold use?
When Harold wrote his equation, the point he used was (7, 3).
When Harold wrote his equation, the point he used was (0, 7).
When Harold wrote his equation, the point he used was (7, 0).
When Harold wrote his equation, the point he used was (3, 7).
Mathematics
2 answers:
ikadub [295]3 years ago
7 0

Answer:

When Harold wrote his equation, the point he used was (7,0).

Step-by-step explanation:

The equation of a linear function in point-slope form :

y-y_1=m(x-x_1)  --A

Where m is the slope

(x_1,y_1) are passing points

Harold's Equation : y = 3(x – 7)

On comparing Harold's Equation with A

x_1=7

y_1=0

Thus the passing point is (7,0).

Hence Option C is correct.

When Harold wrote his equation, the point he used was (7,0).

In-s [12.5K]3 years ago
6 0
I believe answer is 7,0/ hope this helps
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I added a screenshot of the complete question along with the given choices.

<em><u>Answers:</u></em>

w = 10 ft and l = 50 ft ................> second option

w = 20 ft and l = 60 ft ...............> third option

w = 50 ft and l = 40 ft ...............> fifth option

<em><u>Explanation:</u></em>

<u>We are given that:</u>

length should be at least 20 ...........> length ≥ 20

equation for perimeter is : 2l + 2w ≤ 200

<u>We will check each option as follows:</u>

<u>Option 1:</u>

w = 50 ft and l = 10 ft

This option is incorrect as the proposed length is less than 20.

<u>Option 2:</u>

w = 10 ft and l = 50 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(50) + 2(10) = 100 + 20 = 120 ≤ 200

The second condition is also satisfied.

This option is correct

<u>Option 3:</u>

w = 20 ft and l = 60 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(60) + 2(20) = 120 + 40 = 160 ≤ 200

The second condition is also satisfied.

This option is correct

<u>Option 4:</u>

w = 90 ft and l = 30 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(30) + 2(90) = 60 + 180 = 240 > 200

The second condition is not satisfied.

This option is incorrect

<u>Option 5:</u>

w = 50 ft and l = 40 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(50) + 2(40) = 100 + 80 = 180 ≤ 200

The second condition is also satisfied.

This option is correct

Hope this helps :)

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