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3 years ago

Need hep teaching my daughter. Janet went to Resturant and left 20% tip. If tip was $3.20 how much was meal? Solve with equation

Mathematics

1 answer:

Stels [109]3 years ago

6 0

Answer:

The meal was $16.00.

Step-by-step explanation:

since the equation for finding the tip is: decimal of percent times total bill, what you want to do is isolate the bill. you do this by dividing both sides by percent and your equation is total cost = tip/percent

let's say our total equation is x.

x=3.20/0.2

x=16

Now check your work.

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A student borrows $12,000 at a simple interest rate of 4.5% for 5 years. How much interest is ones at the end of 5 years, and wh

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Answer:

$12,000(1+\frac{4.5}{100}*5)=12,000(1.225)=\$14,700$

Step-by-step explanation:

Simple interest is where interest is only accumulated on the principle, so at 4.5% for 5 years, 22.5% is added to the principal.

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3 years ago

Find the length of GF

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By the Pythagorean Theorem:

The square of the hypotenuse (longest side) of a right triangle is equal to the sum of the side lengths squared, or mathematically:

h^2=x^2+y^2, where x and y are the side lengths and h is the length of the hypotenuse, in this case:

9.4^2=6.8^2+GF^2

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3 years ago

Read 2 more answers

Sarah claims that the thickness of the spearmint gum she produces is 7.5 one-hundredths of an inch. A quality control specialist

satela [25.4K]

Answer:

$t=\frac{7.55-7.5}{\frac{0.103}{\sqrt{10}}}=1.539$

$p_v =2*P(t_{(9)}>1.539)=0.158$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis.

Step-by-step explanation:

Data given and notation

Data: 7.65, 7.60, 7.65, 7.7, 7.55, 7.55, 7.4, 7.4, 7.5, 7.5

We can begin calculating the sample mean given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And the sample deviation given by:

$s=\sart{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And we got:

$\bar X=7.55$ represent the sample mean

$s=0.103$ represent the sample standard deviation

$n=10$ sample size

$\mu_o =7.5$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is equal to 7.5 or no, the system of hypothesis would be:

Null hypothesis: $\mu = 7.5$

Alternative hypothesis: $\mu \neq 7.5$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{7.55-7.5}{\frac{0.103}{\sqrt{10}}}=1.539$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=10-1=9$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(9)}>1.539)=0.158$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis.

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