Answer:
Rn RRhHSRHS SR RSW
Step-by-step explanation:
E fSWE SESE Et SET E
A tangent (here WZ in the question) to any circle (here O in the question) is a line segment that touches the circle at only one point (here B in the question) on circumference of circle, and the radius of the circle (here OB in the question) through this point is always perpendicular to that particular tangent.
In other words, Tangent (WZ) and Radius (OB) of any circle (O) always make a Right angle at point of intersection (B) on its circumference.
It means angle ∠OBZ would be a Right angle i.e. 90 degrees.
So, option B i.e. 90 degrees is the final answer.
Answer:
P(AC∪B)=0.9+0.35=1.25
Step-by-step explanation:
I am not sure if A = {E1, E2} and others are combined probability, but try either way and see if it works or not. Are events combined or mutually exclusive?
1. Find P(Ac ∪ B)
Use probability formula (Mutually exclusive): P(A∪B)=P(A)+P(B)
2. Find P(A) and P(B) and P(C)
P(A) = 0.1 * 0.15 or try 0.1 + 0.15
P(A) = 0.0015 or 0.25
P(B) = 0.15 * 0.2 or try 0.15 + 0.2
P(B) = 0.03 or 0.35
P(C) = 0.1 * 0.25 * 0.3 or try 0.1 + 0.25 + 0.35
P(C) = 0.0075 or 0.65
P(AC) = 1.125*10^-5 or 0.9
3. Find answer
P(AC∪B)=P(AC)+P(B)
P(AC∪B)=1.125*10^-5+0.03=0.03
OR
P(AC∪B)=0.9+0.35=1.25
Hi there
Simplified form of -(-10p+4r)
10p-4r
Answer:
(d) 55°
Step-by-step explanation:
Because segment AB is parallel to CD, ∠OAB will also have measure y°. (It is an alternate internal angle with ∠COA created by transversal AO.)
We assume that arc AB, marked "70", has a measure of 70°, which means ∠AOB = 70°.
ABO is an isosceles triangle, so its base angles are equal and the sum of its internal angles is 180°.
... y° + y° + 70° = 180°
... 2y = 110
... y = 55
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<em>Comment on units</em>
The number 70 is not marked as degrees, so we could take it as either an angle measure or an actual length (in which case the problem cannot be worked). A unitless angle measure is radians, but 70 radians makes no sense in this context. (70 radians is 11 full circles plus about 50.7°. "y" would have to be a rather large negative number for the angle measures to sum to 180° in triangle AOB.)
The value of y we found above is 55, so y° is then 55°. It makes no sense in this context for y to be called 55°, because the angle measure would then be ...
... 55°°
a value that has no meaning as an angle measure.